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Marizza181 [45]
2 years ago
14

Henry can lift a 200 N load 20 m up a ladder in 40 s. Ricardo can lift twice the load up one-half the distance in the same amoun

t of time. Which comparison between Ricardo and Henry is correct?
Physics
2 answers:
prohojiy [21]2 years ago
4 0
Henry will lift 200 N load 20 m up a ladder in 40 s.  While the Ricardo will take 400 N load in 80 seconds. So, For Henry to take 400 N load it will take him 80 seconds in two attempts. And,also, he will have to cover 40 m of distance. 
madreJ [45]2 years ago
4 0

Answer;

-Ricardo exerted a greater force, did the same amount of work, and had the same power output as Henry.

Explanation;

For Ricardo to lift twice the load lifted by Henry for the one-half the distance in the same amount of time, he will need more force as the load is heavier.

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A man runs at a velocity of 4.5 m/s for 15.0 min. When going up an increasingly steep hill, he slows down at a constant rate of
madreJ [45]

The man ran  <u>4252.5 meters.</u>

Why?

To solve the problem, we need to divide the exercise into two movements, the first on while the was running at 4.5 m/s for 15 min, and then, while he was slowing down (going up because of the hill).

First movement: Running at 4.5 m/s for 15 min.

We need convert from minutes to seconds,

1min=60seconds\\\\15min*\frac{60seconds}{1min}=900seconds

Now, calculating the distance covered for the first movement, we have:

x_{1}=0+v_{1}*t_{1}\\\\x_{1}=4.5\frac{m}{s}*900s=4050m

So, we know that the man covered 4050m for the first movement, it will be our initial position for the second movement.

Second movement:  acceleration -0.05m/s^2 (because he's slowing down) for 90 seconds, at 4.5m/s.

x_{2}=x_{1}+v_{1}*t+\frac{1}{2}at^{2}\\\\x_{2}=4050m+4.5m\frac{m}{s}*90seconds-\frac{1}{2}*(0.05\frac{m}{s^{2}})*(90s)^{2}\\\\x_{2}=4050m+405m-(0.5*0.05\frac{m}{s^{2}}*8100s^{2})=4050m+405m-202.5m\\\\x_{2}=4252.5m

Hence, we have that he ran 4252.5 m.

Have a nice day!

4 0
2 years ago
Visualize five horizontal sedimentary strata exposed in a cliff or canyon wall identified by consecutive numbers, 1 being the lo
Grace [21]

Answer:

Only the 4 th statement is true that is bed 1 and 3 are older than 4.

Explanation:

The 5 beds are numbered from 1 to 5 , 1 being the lowest and 5 being the topmost bed.

We are given 4 statements and we have to find out which all are true.

(<u>a)Bed 4 is older than bed 2 </u>

This is wrong because the lower beds are older than beds that are higher.

<u>(b)Bed 3 is older than beds 2 and 4</u>

This is also wrong because the 2 is older than 3

(<u>c)Bed 5 is the oldest </u>

This is wrong because bed 1 is the oldest

(<u>d)Beds 1 and 3 are older than 4</u>

This is true as lower beds are older

<u />

6 0
2 years ago
Read 2 more answers
A brick is resting on a rough incline as shown in the figure. The friction force acting on the brick, along the incline, is
Tasya [4]
B) equal to the gravitational force of the brick
6 0
2 years ago
Read 2 more answers
A solid element that is malleable' a good conductor of electricity, and reacts with oxygen is classified as a
Finger [1]
1) metal
Even though metalloids are also conductors of heat and electricity, malleable they are not as good as metals.
Metals are very good conductors of electricity and heat. They are also very hard to touch. Noble gases and non metals are the exact opposite in physical and chemical properties. Metals readily react with oxygen.
5 0
2 years ago
Keisha looks out the window from a tall building at her friend Monique standing on the ground, 8.3 m away from the side of the b
Salsk061 [2.6K]

Answer:

Explanation:

GIVEN DATA:

Distance between keisha and her friend 8.3 m

angle made by keisha toside building 30 degree

height of her friend monique is 1.5 m

from the figure

\Delta ACB

tan 30 = \frac{8.3}{h}

h= \frac{8.3}{tan 30} = 14.376 m

therefore

height of keisha is = h  + 1.5 m

                               = 14.376 + 1.5

= 15.876 \simeq 16 m

therefore option c is correct

5 0
2 years ago
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