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astra-53 [7]
1 year ago
6

A 70kg man spreads his legs as shown calculate the tripping force​

Physics
1 answer:
shutvik [7]1 year ago
6 0

This is simply defined as the energy of an object as an attribute of a physical movement

Force

This is simply defined as the energy of an object as an attribute of a physical movement

it is important to note that a tripping for will be a force opposing motion therefore

For a 70kg man trip on a force the for it must me acted upon by a Force

For more information on this visit

brainly.com/question/21811998

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Reika [66]

Answer:

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Explanation:

For this exercise, let's use the kinematic relations of accelerated motion

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          0 = v₀² - 2 a x

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5 0
2 years ago
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mezya [45]
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kotykmax [81]

Answer:

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4 0
2 years ago
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Reptile [31]

Answer:

PLEASE HELP John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1 m in front of him. In the 5 s time period that follows, John's velocity is given by the velocity versus time graph in the figure. Taking the mailbox to mark the zero location, with positions beyond the mailbox as positive, plot his position versus time in the given position versus time graph. John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1 m in front of him. In the 5 s time period that follows, John's velocity is given by the velocity versus time graph in the figure. Taking the mailbox to mark the zero location, with positions beyond the mailbox as positive, plot his position versus time in the given position versus time graph. Assuming that all the numbers given are exact, what is John's position at a time of 4.79 s ? Enter your answer to at least three significant digits.

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Read 2 more answers
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