The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba
ttery's internal resistance?
2 answers:
Refer to the diagram shown below.
i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω
Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5 (10
Also,
R₂*i = 9.5 (2)
Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A
From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)
Answer: 0.08 Ω
i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω
Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5 (10
Also,
R₂*i = 9.5 (2)
Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A
From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)
Answer: 0.08 Ω
You might be interested in
To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.
By definition we know that the change in entropy is given by
Where,
Q = Heat transfer
T = Temperature
On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is
According to the data given we have to,
PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is
On the other hand,
The total change of entropy would be,
Since the heat engine is not reversible.
PART B)
Work done by heat engine is given by
Therefore the work in the system is 100000Btu
Answer:
a. 1. she informed the audience when she was concluding
2. She simply outlined the steps tying her conclusion to the topic
3. her conclusion was concise and simple.
b. 13.1 grams
Explanation:
a. signalling the end of a speech prepares the mind of the audience and leaves them satisfied, and Kara correctly signaled the end of her speech when she said "In conclusion".
Also, Kara summarized the ideas in her speech by simply outlining the requirements needed to get a U.S passport.
Her conclusion was concise and simple which is very important especially for lengthy speeches because the audience at this point must be getting tired and distracted.
b. Amount of cholesterol in 100 mL of blood = 248 mg
Total Volume of blood = 5.3 Liters.
the question is asking us to find the total grams of cholesterol in the individual's body, that is the total grams of cholesterol in 5.3 Liters of the individuals blood.
To solve, let us use the following steps:
1. unify the units of measuring volume.
since the first volume is given in Milliliters, I will convert the second volume (5.3 Liters) to milliliters too. To do this, note that:
1 liter = 1000 Milliliter (mL)
∴ 5.3 Liters = 5.3 × 1000 = 5300 Milliliters (mL)
2. Calculate the amount of cholesterol in 5300 mL.
100 mL = 248 mg of cholesterol
∴ 1 mL = = 2.48 mg
∴ 5300 mL = 2.48 × 5300 = 13,144 mg of cholesterol.
3. Convert the amount of cholesterol from Milligram to gram
Since the question asked for the gram of cholesterol, not the milligram of cholesterol, converting from milligram to gram, we use the following steps:
1000 mg = 1 g
∴ 1 mg = g
∴ 13144 mg = 13144 × =
= 13.144 ≅ 13.1 g of cholesterol ( 1 decimal place).
I suggest you go and study the conversion relationships between the sub units milli, micro, centi and deci.