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Ivan
2 years ago
10

5. How much does a suitcase weigh if it has a mass of 22.5 kg?

Physics
2 answers:
irga5000 [103]2 years ago
5 0

Answer:

Weight of the suitcase, W = 220.5 N

Explanation:

It is given that,

Mass of the suitcase, m = 22.5 kg

Let W is the weight of the suitcase. The weight of an object is equal to the force acting on it due to the gravity. It is given by the product of mass and acceleration due to gravity.Mathematically, it is given by :

W = mg

W=22.5\times 9.8

W = 220.5 N          

So, the weight of the suitcase is 220.5 N. Hence, this is the required solution.              

Aloiza [94]2 years ago
4 0
27 pounds might be the answer cause 5.4 is 9 pound wick is an average size of an suite case
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A company designed and sells an ultrasonic​ receiver, which detects sounds unable to be heard by the human ear. The receiver can
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Answer:

28√3 m

Explanation:

A = vertex where receiver is placed

S = focus

Bp = r = radius of the outside edge

Bc = 2r = diameter

The full explanation is shown in the picture attached herewith. Thank you and i hope it helps.

7 0
2 years ago
An auto moves 10 meters in the first second of travel, 15 more meters in the next second, and 20 more meters during the third se
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2 years ago
Two workhorses tow a barge along a straight canal. Each horse exerts a constant force of magnitude F, and the tow ropes make an
morpeh [17]

Answer:

<em>a) Fvt cosθ</em>

<em>b) Fv cosθ</em>

<em></em>

Explanation:

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the rope is inclined at an angle = θ

speed of each horse = v

a) In time t, the distance traveled d = speed x time

i.e d = v x t = vt

also, the resultant force = F cosθ

Work done W = force x distance

W = F cosθ x vt = <em>Fvt cosθ</em>

<em></em>

b) Power provided by the horse P = force x speed

P = F cosθ x v

P = <em>Fv cosθ</em>

8 0
1 year ago
Two long, parallel wires carry unequal currents in the same direction. The ratio of the currents is 3 to 1. The magnitude of the
astraxan [27]

Answer:

3A is the larger of the two currents.

Explanation:

Let the currents in the two wires be I₁ and I₂

given:

Magnitude of the electric field, B = 4.0μT = 4.0×10⁻⁶T

Distance, R = 10cm = 0.1m

Ratio of the current = I₁ : I₂ = 3 : 1

Now, the magnitude of a magnetic field at a distance 'R' due to the current 'I' is given as

B = \frac{\mu_oI}{2\pi R}

Where \mu_o is the magnitude constant = 4π×10⁻⁷ H/m

Thus, the magnitude of a magnetic field due to I₁ will be

B_1 = \frac{\mu_oI_1}{2\pi R}

B_2 = \frac{\mu_oI_2}{2\pi R}

given,

B = B₁ - B₂ (since both the currents are in the same direction and parallel)

substituting the values of B, B₁ and B₂

we get

4.0×10⁻⁶T =  \frac{\mu_oI_1}{2\pi R} - \frac{\mu_oI_2}{2\pi R}

or

4.0×10⁻⁶T =  \frac{\mu_o}{2\pi R}\times (I_1-I_2 )

also

\frac{I_1}{I_2} = \frac{3}{1}

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substituting the values in the above equation we get

4.0×10⁻⁶T =  \frac{4\pi\times 10^{-7}}{2\pi 0.1}\times (3 I_2-I_2)

⇒I_2 = 1A

also

I_1 = 3\times I_2

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⇒I_1 = 3A

Hence, the larger of the two currents is 3A

3 0
2 years ago
A wooden disk of mass m and radius r has a string of negligible mass is wrapped around it. If the disk is allowed to fall and th
Tju [1.3M]

Answer:

a = \frac{2}{3}g

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also by torque equation we can say

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a = \frac{2}{3}g

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7 0
2 years ago
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