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Otrada [13]
2 years ago
8

Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of

50 kilograms. What can Paul do to increase the bike’s kinetic energy?
A. He can let Ivan off at the next stop.
B. He can pedal harder to increase the rate to 10 meters/second.
C. He can reduce the speed to 3 meters/second.
D. He can pick up a third rider.
Physics
2 answers:
Sonbull [250]2 years ago
5 0
The formula is Ke = 1/2 m v^2
The two of them together have a Ke of mv^2. So you either increase m or v. That's what makes the problem difficult. He can do D or B. We have to choose.

A is no solution. The Ke goes down because Paul loses Ivan's mass.
C is out of the question 3 meters/sec is a big reduction from 5 m/s. So now what do we do about B and D?

The question is what does the third person add. The tandoms I've peddled only allow for 1 or 2 people to add to the motion. So the third person only adds mass. He does not have a v that he is contributing to. To say that he is going 5m/s is true, but he's not contributing anything to that motion.

I pick B, but it is one of those questions that the correctness of it is in the head of the proposer. Be prepared to get it wrong. Argue the point politely if you agree with me, but back off as soon as you have presented your case.

B <<<<====== answer. 
alisha [4.7K]2 years ago
5 0

Answer: The correct answer is option C.

Explanation:

Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:

K.E.=\frac{1}{2}mass\times (velocity)^2

Kinetic energy depends upon the mass and velocity of the an object.

So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.

Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion

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Answer:

Specific gravity of other fluid = .854 (Approx)

Explanation:

Given:

Mass of water = 35 g

Mass of filled bottle with water = 98.44 g

Mass of filled bottle with fluid = 89.22 g

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Mass of water = 98.44g - 35g = 63.44g

Density of water = 1000 g/L

Volume of bottle = 63.44/1000 = 0.06344L

Mass of other liquid = 89.22g - 35g = 54.22g

Density of other liquid = 54.22g/0.06344L = 854.665826 g/L

Water has a specific gravity = 1

So ,  specific gravity of other fluid

1000 / 854.665826 = 1 / specific gravity of other fluid

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1 year ago
The reaction energy of a reaction is the amount of energy released by the reaction. It is found by determining the difference in
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Explanation:

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m = 4.00260 u + 222.01757 u = 226.02017 u .

The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is

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Delta E = (0.00523 u)*(931.5MeV/1u)

Delta E = 4.87 MeV

Converting  4.87 MeV to Joules

1 joule [J] = 6241506363094 mega-electrón voltio [MeV]

4 mega-electrón voltio = 6.40870932 x 10^(-13) joule

4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule

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Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

2 n t = (m + \dfrac{1}{2})\lambda

At m = 0 for the minimum thickness, so

2\times 1.45 \times t = (0 + 0.5)\times 600

2.9 \times t =300

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If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees

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Explanation:

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