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vekshin1
2 years ago
6

A singly-charged ion enters a velocity selector that has a 0.18-T magnetic field perpendicular to an electric field of 1.6 kV/m,

with both fields perpendicular to the velocity of the ion. The same magnetic field is then used to deflect the ion into a circular path of radius 12.5 cm. What velocity was selected by the velocity selector?
Physics
1 answer:
lesya692 [45]2 years ago
8 0

Answer: a) 8.9km/s b) 4.05 x 10^-25 kg

Explanation:

a)

To find the velocity, 

V = E/B plug in the numbers we get

V = 1.6kV/m / 0.18 T = 8.9 km/s 



b)

To find the ion mass, 

m = erB^2/E = 0.125 m x 1.6x10^-19 x (0.18)^2 / ( 1.6 x 10 ^ 3 V/m ) = 4.05 x 10 ^ -25 kg

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A person travels distance πR along the circumference
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Answer: 2R

Explanation:

Here the person travels пR distance. We know that the circumference of a circle is 2πR. So your imaginated person has traveled the distance which​ is half of the circumference of the circle. And this distance is equal to its diameter. We know that diameter of a circle is two times larger than the radius. So the person's displacement is two times of the radius, means 2R. [Here 'R' means the radius of the circle]

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2 years ago
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Match each type of consequence with its resulting behavior change
ira [324]

Answer:

Janet stops parking in handicapped spaces after she gets a big parking ticket. - Positive Punishment

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Sally increases the amount of work she completes to receive more pay. - Positive Reinforcement

Explanation:

In operant conditioning, the main principle is that behavior increases or decreases its frequency depending on whether it's reinforced or punished. A behavior can be reinforced by giving something the subject appreciates, like more pay for their work (positive reinforcement) or taking away something they dislike, like late fees (negative reinforcement). Punishments work the same way, you can give something the subject dislikes, like a parking ticket, (positive punishment) or taking away something they like recess for a child. (negative punishment).

5 0
2 years ago
A tennis player hits a ball 2.0 m above the ground. The ball leaves his racquet with a speed of 20 m/s at an angle 5.0 ∘ above t
ipn [44]

Answer:

ball clears the net

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\theta = angle of launch = 5 deg

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v_{ox} = initial velocity = v_{o} Cos\theta = 20 Cos5 = 19.92 ms^{-1}

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Since there is no acceleration along the horizontal direction, we have

X = v_{ox} t \\7 = v_{ox} t\\t = \frac{7}{v_{ox}}       Eq-1

Consider the motion of the ball along the vertical direction

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t = time of travel

Y_{o} = Initial position of the ball at the time of launch = 2 m

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Y = Y_{o} + v_{oy} t + (0.5) a_{y} t^{2}\\Y = 2 + (20 Sin5) (\frac{7}{20 Cos5}) + (0.5) (- 9.8) (\frac{7}{20 Cos5})^{2}\\Y = 2.00758 m\\

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7 0
2 years ago
A rod with a rest length of 1m whizzes past an observer at a speed of 0.995c, where c is the speed of light. Is it possible that
Tresset [83]

Answer:

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L = observed length of the rod

\gamma = Lorentz factor

\gamma\equiv \frac{1}{\sqrt{1-\frac{v^2}{c^2} } }

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Lubov Fominskaja [6]

Positions. Happy to help! Please mark as Brainliest!

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