Answer:
q2 must also be doubled
r may also be halved
Explanation:
According to Coulumbs law
F= K q1 q2/r^2
If q1 is doubled, we must necessarily double q2 and r may also be halved in order to maintain F at the same value. Once the value of F is thus kept constant and E is also constant, the product FE must remain constant.
Assuming that this gas is in ideal state, we can use the relation that for every 1 mol of an ideal gas it would have a volume of 22.4 L. But before using this, relation we need to convert the number of grams of H2 into moles by using the molar mass of 2.02 g/mol.
moles H2 = 0.00922 g ( 1 mol / 2.02 g ) = 0.005 mol H2
Volume H2 at STP = 0.005 mol H2 ( 22.4 L / 1 mol ) = 0.102 L of H2
Answer:
I believe the correct answer would be A :)
Explanation:
P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
