Answer:
0.01
Explanation:
Given the data:
10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, 9.90
True value = 9.81
Mean value :
Σx / n
Sample size, n = 9
(10.1 + 9.87 + 9.76 + 9.91 + 9.75 + 9.88 + 9.69 + 9.83 + 9.90) / 9
= 88.69 / 9
= 9.854
Standard deviation (σ) :
Sqrt (Σ(X - m)² / n)
[(10.1 - 9.854)^2 + (9.87 - 9.854)^2 + (9.76 - 9.854)^2 + (9.91 - 9.854)^2 + (9.75 - 9.854)^2 + (9.88 - 9.854)^2 + (9.69 - 9.854)^2 + (9.83 - 9.854)^2 + (9.90 - 9.854)^2] / 9
Sqrt(0.113824 / 9)
Sqrt(0.0126471)
σ = 0.1124593
Standard Error = σ / sqrt(n)
Standard Error = 0.1124593 / 9
Standard Error = 0.0124954
Standard Error = 0.01 ( 1 significant digit)
Answer:
C. At maximum displacement, its instantaneous acceleration is also at maximum.
Explanation:
Lets take
The general equation of the SHM
Displacement
x= A sinω t
velocity
V= Aω cosω t
Acceleration
a= -Aω² sinω t
Form the above we can say that displacement and the acceleration are in the same phase.
Therefore when displacement is maximum then acceleration also will be maximum.
Therefore the answer is C.
<span>Based
on Newton's law of universal gravitation, the equation for the
gravitational force exerted by an object on another object is given by:
F = Gm1m2/(r^2)
where G is the universal gravitational constant, F is the gravitational
force exerted, m1 is the mass of the first object, m2 is the mass of the
second object, and r is the separation distance between the two
objects.
If the mass of both objects were doubled, then we would have: m1' * m2' =
(2m1) * (2m2) = 4m1m2. Assuming r stays constant (G is a constant so
that won't change anyway), then this means that the new force will be 4
times greater, ie 8N * 4 = 32N of gravitational force. </span>
Answer:
Explanation:
Intensity of unpolarized light = I(o)
Intensity of light after first polarization by polarizer A. = I(o)/2
Angle between A and B = 120 degree.
Intensity of light after second polarization = I Cos² θ
= I(o) /2 x cos²120 = I(o) /8 .
Angle between B and C is 70 degree
Intensity of light after third polarization =
I(o)/8 x Cos² 70 = 0.1156 x I (o) /8 =
Required ratio =.01445
a. As sun peeks, it creates a straight line- sun to tree to shadow, angle=180°
b. During morning, the sun-tree-shadow changes from 180° to 90°, during noon, angle =90°.During sunset the angle changes from 90 to 0°.
c. Acute angles created in afternoon.
d. A right angle would be created at noon.
e. Obtuse angle would be created in morning.
f. Yes, a straight angle would be created at sunrise.
g. When sun is at mid-morning, the angle=45°+90°= 135°
