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ankoles [38]
2 years ago
10

Emir is standing in a treehouse and looking down at a swingset in the yard next door. The angle of depression from Emir's eyelin

e to the swingset is 33.69°, and Emir is 10 feet from the ground. How many feet is the base of the tree from the swingset? Round your answer to the nearest foot.
Physics
2 answers:
lara [203]2 years ago
4 0

Answer:

15 ft

Explanation:

We use tangent of angles. Let Ф = angle of depression of Emir's line of sight = angle of elevation of base of swingset from Emir = 33.69°. Let x = height of tree = 10 ft and y = distance of base of tree from swingset.

So tanФ = x/y and y = x/tanФ

y = x/tanФ

= 10 ft/tan33.69°

= 15 ft

nlexa [21]2 years ago
4 0

Answer:

15 ft

Explanation:

took the test got it right

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You perform nine (identical) measurements of the acceleration of gravity (units of m/s2): 10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.6
AveGali [126]

Answer:

0.01

Explanation:

Given the data:

10.1,9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, 9.90

True value = 9.81

Mean value :

Σx / n

Sample size, n = 9

(10.1 + 9.87 + 9.76 + 9.91 + 9.75 + 9.88 + 9.69 + 9.83 + 9.90) / 9

= 88.69 / 9

= 9.854

Standard deviation (σ) :

Sqrt (Σ(X - m)² / n)

[(10.1 - 9.854)^2 + (9.87 - 9.854)^2 + (9.76 - 9.854)^2 + (9.91 - 9.854)^2 + (9.75 - 9.854)^2 + (9.88 - 9.854)^2 + (9.69 - 9.854)^2 + (9.83 - 9.854)^2 + (9.90 - 9.854)^2] / 9

Sqrt(0.113824 / 9)

Sqrt(0.0126471)

σ = 0.1124593

Standard Error = σ / sqrt(n)

Standard Error = 0.1124593 / 9

Standard Error = 0.0124954

Standard Error = 0.01 ( 1 significant digit)

3 0
2 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from
hodyreva [135]

Answer:

C. At maximum displacement, its instantaneous acceleration is also at maximum.

Explanation:

Lets take

The general equation of the SHM  

Displacement

x= A sinω t

velocity

V=  Aω cosω t

Acceleration

a= -Aω² sinω t

Form the above we can say that displacement and the acceleration are in the same phase.

Therefore when displacement is maximum then acceleration also will be maximum.

Therefore the answer is C.

5 0
2 years ago
Two objects exert a gravitational force on 8 N on one another. What would that force be if the mass of BOTH objects were doubled
seropon [69]
<span>Based on Newton's law of universal gravitation, the equation for the gravitational force exerted by an object on another object is given by:
F = Gm1m2/(r^2)
where G is the universal gravitational constant, F is the gravitational force exerted, m1 is the mass of the first object, m2 is the mass of the second object, and r is the separation distance between the two objects.
If the mass of both objects were doubled, then we would have: m1' * m2' = (2m1) * (2m2) = 4m1m2. Assuming r stays constant (G is a constant so that won't change anyway), then this means that the new force will be 4 times greater, ie 8N * 4 = 32N of gravitational force. </span>
4 0
2 years ago
The following items are positioned in sequence: A source of a beam of natural light of intensity I0, three ideal polarizers A, B
statuscvo [17]

Answer:

Explanation:

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Intensity of light after first polarization by polarizer A. = I(o)/2

Angle between A and B = 120 degree.

Intensity of light after second polarization = I Cos² θ

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Intensity of light after third polarization =

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5 0
2 years ago
There is a tree standing in the desert; the sun is rising to the east.
aksik [14]

a. As sun peeks, it creates a straight line- sun to tree to shadow, angle=180°

b. During morning, the sun-tree-shadow changes from 180° to 90°, during noon, angle =90°.During sunset the angle changes from 90 to 0°.

c. Acute angles created in afternoon.

d. A right angle would be created at noon.

e. Obtuse angle would be created in morning.

f. Yes, a straight angle would be created at sunrise.

g. When sun is at mid-morning, the angle=45°+90°= 135°

5 0
2 years ago
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