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cricket20 [7]
2 years ago
5

Which of the following statements characterizing types of waves are true?

Physics
1 answer:
Tasya [4]2 years ago
7 0

Answer:

a and b.

Explanation:

In general  types of wave

1. Transverse wave  :

    In these waves particle are vibrate perpendicular to motion of waves.

 Ex : Electromagnetic wave , Radio wave .

2. Longitudinal wave :

   In these waves particle are vibrate along the motion of waves.

 Ex : Sound wave

Mechanical wave  :

1 .These are transverse wave or Longitudinal wave or combination of them .

2.These waves required medium for propagation.

3. The particle are vibrate perpendicular to motion of waves.

So the option a and b are correct.

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Jordan wants to know the difference between using a 60-W and 100-W lightbulb in her lamp. She calculates the energy it would tak
Andreas93 [3]

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

E = P*t

Where P is the power and t is the time

For the 60 W lightbulb:

E_{60} = P*t = 60 W*30 s = 1800 J

For the 100 W lightbulb:

E_{100} = P*t = 100 W*30 s = 3000 J

Hence, the difference in the amount of energy transferred is:

E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

4 0
1 year ago
What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?
Stells [14]
This is simple question and easy to understand.
so first you use a formula to calculate frequency of the wave.
v _ stands for velocity a.k.a speed
f_ stands for frequency which you have to find.
(pronounced lemda)_ stands for wavelength.
Then you gonna place all your values according to you have in the formula as shown then solve for f.
Finally, you use the time formula
where
T_ is period a.k.a time which equal to the reciprocal of frequency or equal to 1/f.
Simply input your values according to the formula and you your answer as 0.5s

8 0
1 year ago
Read 2 more answers
To navigate, a porpoise emits a sound wave that has a wavelength of 2.2 cm. The speed at which the wave travels in seawater is 1
Alenkasestr [34]

To solve this problem we will apply the concept related to frequency, by which it is defined as the relationship between the speed of the wave and the wavelength. Since the frequency is the inverse of the period, this relationship will also be reversed. That is to say,

f = \frac{v}{\lambda}

Here,

v = Velocity

\lambda = Wavelength

Now the period is defined as,

T = \frac{1}{f}

Therefore

T = \frac{\lambda}{v}

Replacing we have that,

T = \frac{2.2*10^{-2}}{1522}

T = 1.445*10^{-5}s

Therefore the period of the wave is 1.445*10^{-5}s

3 0
2 years ago
Suppose a plot of inverse wavelength vs frequency has slope equal to 0.119, what is the speed of sound traveling in the tube to
strojnjashka [21]

Answer:

8.40 m/s

Explanation:

Slope of the plot is 0.119

Slope of a plot is given by the change in y direction divided by the change in x direction

Here, the y axis represents inverse wavelength and the x axis represents frequency.

f = Frequency (Hz, assumed)

v = Phase velocity (m/s, assumed)

λ = Wavelength (m, assumed)

So, slope

m=\frac{\frac{1}{\lambda}}{f}

Now,

\lambda=\frac{v}{f}\\\Rightarrow \lambda^{-1}=\frac{f}{v}

\\\Rightarrow m=\frac{\frac{f}{v}}{f}\\\Rightarrow 0.119=\frac{1}{v}\\\Rightarrow v=\frac{1}{0.119}\\\Rightarrow v=8.40\ m/s

The speed of sound travelling in the tube is 8.40 m/s

5 0
2 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. In a survey conduc
jarptica [38.1K]

Answer: The expected population that wants flexible working hours in ranging from 58% to 62 %.

Explanation:

Percentage of sample respondents agreed for flexible working hours = 60%

The margin of the error = ± 2%

The expected population that wants flexible working hours in ranging from:

\text{percentage of agreed}-2\% lower range

\text{percentage of agreed}+\2% upper range

60\%-2\% to 60\%+2\% that is 58% to 62 %.

The expected population that wants flexible working hours in ranging from 58% to 62 %.

3 0
2 years ago
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