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1 year ago

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Jordan wants to know the difference between using a 60-W and 100-W lightbulb in her lamp. She calculates the energy it would tak

e to use each bulb for 30 s by using this equation: Power = Energy transferred (J)/time (s) What is the difference in the amount of energy transferred by the two bulbs during this time?

1 answer:

Andreas93 [3]1 year ago

4 0

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

$E = P*t$

Where P is the power and t is the time

For the 60 W lightbulb:

$E_{60} = P*t = 60 W*30 s = 1800 J$

For the 100 W lightbulb:

$E_{100} = P*t = 100 W*30 s = 3000 J$

Hence, the difference in the amount of energy transferred is:

$E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J$

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

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$n_{H} = \frac{d_{H}}{x}$

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