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hjlf
2 years ago
5

A 1.7-kg block of wood rests on a rough surface. A 0.011-kg bullet strikes the block with a speed of 670 m/s and embeds itself.

The bullet-block system slides forward 2.4 m before coming to rest.
Physics
1 answer:
aksik [14]2 years ago
7 0

What is the coefficient of kinetic friction between the block and the surface?  Express your answer using two significant figures.

Answer:

0.39

Explanation:

Given information

m1=1.7 Kg

m2=0.011 Kg

v2=670 m/s

d=2.4 m

m2v2=(m1+m2)v hence v=\frac {m2v2}{m1+m2} and also a=\frac {v^{2}}{2d}

The deceleration due to friction is given by

F=\mu_k N=\mu_k W=\mu_k (m1+m2)g

F=(m1+m2)a=\mu_k (m1+m2)g therefore a=\mu_k g

Therefore, a=\frac {v^{2}}{2d}=\mu_k g

\mu_k=\frac {1}{2dg}(\frac {m2v}{m1+m2})^{2}=\frac {1}{2*2.4*9.81}\times (\frac {0.011*670}{1.7+0.011})^{2}

\mu_k=0.39

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At 213.1 K a substance has a vapor pressure of 45.77 mmHg. At 243.7 K it has a vapor pressure of 193.1 mm Hg. Calculate its heat
vlabodo [156]

Answer:

20.3125 kJ/mol

Explanation:

P_{i} = initial vapor pressure = 45.77 mm Hg

P_{f} = final vapor pressure = 193.1 mm Hg

T_{i} = initial temperature = 213.1 K

T_{f} = final temperature = 243.7 K

H = Heat of vaporization

Using the equation

ln\left ( \frac{P_{f}}{P_{i}} \right ) = \left ( \frac{-H}{R} \right )\left ( \frac{1}{T_{f}} - \frac{1}{T_{i}}\right)

ln\left ( \frac{193.1}{45.77} \right ) = \left ( \frac{-H}{8.314} \right )\left ( \frac{1}{243.7} - \frac{1}{213.1}\right)

H = 20312.5 J/mol

H = 20.3125 kJ/mol

8 0
2 years ago
Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop
anastassius [24]
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F = ma
4.9 = 0.5a
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Hope this answers the question. Have a nice day.

4 0
2 years ago
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Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50
defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0
2 years ago
You throw a baseball at an angle of 30.0∘∘ above the horizontal. It reaches the highest point of its trajectory 1.05 ss later. A
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Answer:

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θ = angle of throw above the horizontal

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u = (1.05 × 9.8)/0.5

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I think that the answer is c but I’m not sure
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