answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
den301095 [7]
2 years ago
15

An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the

new acceleration would be _____ m/s/s.
Physics
1 answer:
alexandr402 [8]2 years ago
5 0

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

You might be interested in
What is the volume of an irregularly shaped object that has a mass 3.0 grams and a density of 6.0 g/mL
pogonyaev

Answer: The volume of an irregularly shaped object is 0.50 ml

Explanation:

To calculate the volume, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of object = 6.0g/ml

mass of object = 3.0 g

Volume of object = ?

Putting in the values we get:

6.0g/ml=\frac{3.0g}{\text{Volume of substance}}

{\text{Volume of substance}}=0.50ml

Thus the volume of an irregularly shaped object is 0.50 ml

4 0
2 years ago
What is the gravitational force of attraction between a planet and a 17-kilogram mass that is falling freely toward the surface
PolarNik [594]

Answer:

a. 150 N

Explanation:

Gravitational Force: This is the force that act on a body under gravity.

The gravitational force always attract every object on or near the earth's surface. The earth therefore, exerts an attractive force on every object on or near it.

The S.I unit of gravitational force is Newton(N).

Mathematically, gravitational force of attraction is expressed as

(i) F = GmM/r² ........................ Equation 1 ( when it involves two object of different masses on the earth)

(ii) F = mg ............................... Equation 2 ( when it involves one mass and the gravitational field).

Given: m = 17 kg, g = 8.8 m/s²

Substituting into equation 2,

F = 17(8.8)

F = 149.6 N

F ≈ 150 N.

Thus the gravitational force = 150 N

The correct option is a. 150 N

5 0
2 years ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
2 years ago
If you drive through water, your brakes may become slippery and ineffective. To dry the brakes off, __________.
GenaCL600 [577]

Answer:

I am not a driver, but I think it's C.

Explanation:

6 0
2 years ago
Read 2 more answers
A uniform metal bar is 5.00 m long and has mass 0.300 kg. The bar is pivoted on a narrow support that is 2.00 m from the left-ha
Firlakuza [10]

Explanation and answer:

This type of question can be clarified and sometimes solved by drawing a proper diagram or sketch.  (see below)

Solution:

Since we do not know the reaction of the support, we can take moments about the support (thereby eliminating its involvement).

CCW moment = 0.900(5.00/2 - x) kg-m

CW moment = 0.300*(5.00/2-2.00)) = 0.150 kg-m

At equilibrium, CCW moment = CW moment, so

0.900(2.50-x) = 0.150

Expand and solve

2.25 - 0.900x = 0.150

0.900x = 2.25-0.15 = 2.10

x = 2.10 / 0.900 = 2.33 m  (to nearest cm)

8 0
2 years ago
Other questions:
  • What body process converts physical energy to electrical energy?
    9·1 answer
  • Tony uses the device shown in the diagram to model how an electromagnet is used in his uncle’s scrap metal yard. After picking u
    14·2 answers
  • Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in
    12·2 answers
  • If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
    12·2 answers
  • B. A hydraulic jack has a ram of 20 cm diameter and a plunger of 3 cm diameter. It is used for lifting a weight of 3 tons. Find
    13·1 answer
  • Calculate the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun
    14·1 answer
  • A 5kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Draw a fo
    10·1 answer
  • A very long line of charge with charge per unit length +8.00 μC/m is on the x-axis and its midpoint is at x = 0. A second very l
    11·1 answer
  • Four friends push on the same block in different directions. Allie pushes on the block to the north with a force of 18 N. Bill p
    10·1 answer
  • Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!