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Dmitriy789 [7]
2 years ago
8

It takes 146./kjmol to break an oxygen-oxygen single bond. calculate the maximum wavelength of light for which an oxygen-oxygen

single bond could be broken by absorbing a single photon.
Physics
1 answer:
erastova [34]2 years ago
8 0
To answer this question, we will use the following rule:
E = hc / lambda where:
E is the energy = 146 kJ/mol = 146000 J/mol
h is Planck's constant = 6.62*10^-34 kg m^2 / sec
c is the speed of light = 3*10^8 m/sec
lambda is the wavelength that we need to calculate 

Substitute with the given values in the above equation to get lambda as follows:
146000 = (6.62 * 10^-34 * 3 * 10^8) / lambda
lambda = 1.36*10^-30 meters
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A steel cylinder at sea level contains air at a high pressure. Attached to the tank are two gauges, one that reads absolute pres
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C) The pressure reading stays the same.

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At its lowest setting a centrifuge rotates with an angular speed of ω1 = 250 rad/s. When it is switched to the next higher setti
dalvyx [7]

Answer:

Part(a): The angular acceleration is 5.63~rad~s^{-2}.

Part(b): The angular displacement is 2629~rad.

Explanation:

Part(a):

If \omega_{1},~\omega_{2}~and~\alpha be the initial angular speed, final angular speed and angular acceleration  of the centrifuge respectively, then from rotational kinematic equation, we can write

\alpha = \dfrac{\omega_{2} - \omega_{1}}{t}......................................................(I)

where 't' is the time taken by the centrifuge to increase its angular speed.

Given, \omega_{i} = 250~rad~s^{-1}, \omega_{f} = 750~rad~s^{-1} and t = 9.5~s. From equation (I), the angular acceleration is given by

\alpha = \dfrac{750 - 250}{9.5}~rad~s^{-2} = 5.63~rad~s^{-2}

Part(b):

Also the angular displacement (\Delta \theta) can be written as

&&\Delta \theta = \omega_{1}~t + \dfrac{1}{2}\alpha~t^{2}\\&or,& \Delta \theta = (250 \times 9.5 + \dfrac{1}{2} \times 5.63 \times 9.5^{2})~rad = 2629~rad

8 0
2 years ago
A 12 volt car battery produces more current than a 1.5 volt battery for a TV remote because...
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This question is loaded with misleading, marginally meaningful phrases.

A 12V battery produces more current than a 1.5V battery produces,
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Of the choices offered, choice 'C' is the closest.  But it should say
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3 0
2 years ago
A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float
storchak [24]

Answer:

 t ’= \frac{1450}{0.6499 + 2 v_r},  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= \frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \  + 2 \ v_r}

      t ’= \frac{1450}{0.6499 + 2 v_r}

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= \frac{ 1450}{ 0.6499 + 2 \ 1}

      t ’= 547.19 s

8 0
2 years ago
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