Answer:
53.63 μA
Explanation:
radius of solenoid, r = 6 cm
Area of solenoid = 3.14 x 6 x 6 = 113.04 cm^2 = 0.0113 m^2
n = 17 turns / cm = 1700 /m
di / dt = 5 A/s
The magnetic field due to the solenoid is given by
B = μ0 n i
dB / dt = μ0 n di / dt
The rate of change in magnetic flux linked with the solenoid =
Area of coil x dB/dt
= 3.14 x 8 x 8 x 10^-4 x μ0 n di / dt
= 3.14 x 64 x 10^-4 x 4 x 3.14 x 10^-7 x 1700 x 5 = 2.145 x 10^-4
The induced emf is given by the rate of change in magnetic flux linked with the coil.
e = 2.145 x 10^-4 V
i = e / R = 2.145 x 10^-4 / 4 = 5.36 x 10^-5 A = 53.63 μA
Answer:
The objects must have the same acceleration and the objects must exert the same magnitude force on each other.
Explanation:
The objects must have the same weight: FALSE. This is not needed, any two object can move together in contact no matter their mass.
The objects must have the same acceleration: TRUE. If they have different accelerations, they will separate since the distance each of them travel at a given time will be different.
The objects must have the same net force acting on them: FALSE. This is not needed, since what matters is acceleration, and a=F/m, so if both objects have different net force acting on them, they could have different masses also to compensate and result in the same acceleration.
The objects must exert the same magnitude force on each other: TRUE, this is the 3rd Newton Law, an action must follow the same reaction.
Answer:
Hydraulic press is called an instrument for multiplication of force. Why? Because it uses Pascal's idea and principle: F=p*S. If we apply small force to small piston you will generate a pressure. According to Pascal's law pressure is the same everywhere in closed system so the same pressure will act on large piston on the other side too.
Explanation:
Voltage = (current) x (resistance)
The voltage across THIS RESISTOR is
V = (0.050 A) x (0.1 ohm)
V = 0.005 v (5 millivolts)
Answer: a)235.9*10^-6 V; b) 471.8 *10^-6 V; c) 1.08*10^-13 J
Explanation: In order to explain this problem we have to use the expression for a capacitor od two parallel plates, which is given by:
C=Q/V where Q and V are the charge and voltage difference in teh capacitor, respectively.
Then we have;
V=Q/C=920*10^-12/(3.9*10^-6)= 235.9*10^-6 V
If we double the separation between the plates, the potencial difference will be: ( Q is constant)
Vnew=Q/Cnew where Cnew is given by;
Cnew=ε *A/(2*d) = 1/2*(ε *A/d)=1/2* Co ; then:
Vnew=2*Q/(Co)=2*Vo=2*4.24 *10^3 V=471.8 *10^-6 V
Finally, the work made oin the capacitor is the difference of the final and initial potential energy so:
Uo=Q^2/(2Co)=
Uf= Q^2/(2Cnew) Cnew=Co/2
W=Uf-Uo= Q^2(1/Co)-Q^2(1/2*Co)=Q^2(1/2*Co)=1.08*10^-13 J
