Answer:
17 m/s south
Explanation:
= Mass of dog = 10 kg
= Mass of skateboard = 2 kg
v = Combined velocity = 2 m/s
= Velocity of dog = 1 m/s
= Velocity of skateboard
In this system the linear momentum is conserved

The velocity of the skateboard will be 17 m/s south as the north is taken as positive
Answer:
F = 2.01*10^-16N -^k
Explanation:
In order to calculate the magnetic force perceived by the bee, you use the following formula:
(1)
q: charge of the bee = 1pC = 1*10^-12 C
The average speed of a bee and the magnetic field of the earth are:
v = 6.70m/s
B = 30*10^-6 T
The bee is flying to the west (-^i). You consider that the magnetic field direction is to the north (^j). Then, the direction of the magnetic force is:
-^i X ^j = -^k
You replace the values of the parameters in the equation (1), in order to calculate the magnitude of the force:

The magnetic force perceived by the bee is 2.01*10^-16N in the -^k direction, that is, toward the ground
Answer:
Explanation:
Let electric potential at A ,B and C be Va , Vb and Vc respectively.
Work done = charge x potential difference
Wab = q ( Va - Vb )
Wac = q ( Va - Vc )
Given
Wac = - Wab / 3
3Wac = - Wab
Now
Wbc = q ( Vb - Vc )
= q [ ( Va-Vc ) - ( Va - Vb )]
= Wac - Wab
= Wac + 3Wac
= 4Wac
Answer:
the hypotenuse = 13.78 cm
Ф = 27.44°
θ = 62.56°
explanation:
Answer: y = 2.4×10^-6m or y= 2.4μm
Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as
y = R×mλ/d
Where y = distance between nth fringe and Central bright spot fringe.
m = position of fringe = 4
λ = wavelength of light= 600nm = 600×10^-9 m
d = distance between slits = 1.50×10^-5m
R = distance between slit and screen = 2m
y = 2 × 4 × 600×10^-9/2
y = 4800×10^-9/2
y = 2400 × 10^-9
y = 2.4×10^-6m or y= 2.4μm