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1 year ago

Two wheels are identical but wheel b is spinning with twice the angular speed of wheel

1 answer:

6 0

<span>If two wheels are exactly the same but spin at different speeds, wheel b is twice te speed of wheel a, it is possible to find the ratio of the magnitude of radial acceleration at a singular point of the rim on wheel be to the spot is four.</span>

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The amusement park ride shown above takes riders straight up a tall tower and then releases an apparatus holding seats. This app

Natasha2012 [34]

The gravitational force on the rider is:

- Way up: equal to mg

- Way down: equal to mg

Explanation:

The choices are missing: find them in the attached figure.

The force of gravity acting on a body is a force directed downward (towards the Earth's centre) and whose magnitude is

$F=mg$

where

m is the mass of the body

g is the acceleration due to gravity

The value of g is approximately constant near the Earth's surface and it is

$g=9.8 m/s^2$

During the ride, the mass of the rider, m, remains constant. This means that the magnitude of the gravitational force, mg, exerted on the rider remains constant during the rider.

Therefore, the correct answer is

- Way up: equal to mg

- Way down: equal to mg

Learn more about force of gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

7 0

2 years ago

An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m

aniked [119]

Answer: The released electromagnetic wave will travel in +y direction

Explanation:

It should be noted that, in a situation, whereby an excited hydrogen atom releases an electromagnetic wave to return to its normal state. And it's also evident that the futuristic dual electric/magnetic field tester on the electromagnetic wave to find the directions of the electric field and magnetic field is used. Eventually, your device tells you that the electric field is pointing in the positive y direction and the magnetic field is pointing in the positive x direction. Therefore, the released electromagnetic wave will travel in +y direction.

7 0

1 year ago

Suppose the foreman had released the box from rest at a height of 0.25 m above the ground. What would the crate's speed be when

Arturiano [62]

Answer:

v = 2.21 m/s

Explanation:

The foreman had released the box from rest at a height of 0.25 m above the ground.

We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :

$mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 0.25} \\\\v=2.21\ m/s$

So, its velocity at the bottom of the ramp is 2.21 m/s.

4 0

1 year ago

Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.

Mariana [72]

Answer: The answer would be no reaction.

Explanation:

7 0

2 years ago

Read 2 more answers

THE RELATIVE ANGLE AT THE KNEE CHANGES FROM 0O TO 85O DURING THE KNEE FLEXION PHASE OF A SQUAT EXERCISE. IF 10 COMPLETE SQUATS A

Mice21 [21]

Answer: angular distance = 1700° and 29.7 rad

also the angular displacement = 0

Explanation:

To explain this, i will give a breakdown of this works.

we are asked to find both the angular distance and displacement the knee undergo.

Ok to get the distance of the knee, we would first take note that for one to squat down and get back up, the knee would travel through 85° of flexion to gpo down, and also through another 85° of extension to return standing (upright). So, the actual angular distance of the squat is 170°.

taking ten squats, the knee would have to go through 170° motion times 10 i.e;

10 * 170° = 1700°

Therefore the angulaar distance is 1700°

now converting this distance to radians since we will be required to have our answer in both degree and rad.

Given that 2pi = 360°, it means that one degree will give 57.3°;

∅ (rad) = ∅ (deg) * 2π/360°

∅ (rad) = 1170° * 2π/360° = 29.7 rad

∅ (rad) = 29.7 rad

b. For the other part, let us remember that angular displacement is equal to angular distance divided by time, so the angular displacement displacement of the knee will be zero, because the knee's position at the final third will be the same as the initial position.

cheers i hope this helps!!!!

5 0

2 years ago