Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is

and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

Answer: (A) velocity = 2.8m/s
(B) Average force = 1.9536 Newtons
Explanation:
Find detailed explanation in the attached picture
<u>Answer:</u>
Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.
<u>Explanation:</u>
Let the east point towards positive X-axis and north point towards positive Y-axis.
Speed of truck = 25 m/s north = 25 j m/s
Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s
= (1.43 i + 1.00 j) m/s
Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j
Magnitude of velocity = 26.04 m/s
Angle from positive horizontal axis = 86.85⁰
So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.
Answer:
Work done by friction along the motion is given as

Explanation:
As per work energy theorem we can say
Work done by all forces = change in kinetic energy of the system
so here car is moving from bottom to top
so here the change in kinetic energy is total work done on the car
so here we will have


now plug in all data in it



Answer:
The moun lives 2.198*10^-6 s as measured by its own frame of reference
The Earth moved 648 m as measured by the moun's frame of reference
Explanation:
From the point of view of the observer on Earth the muon traveled 3.53 km at 0.983c
0.983 * 3*10^8 = 2.949*10^8 m/s
Δt = d/v = 3530 / 2.949*10^8 = 1.197*10^-5 s
The muon lived 1.197*10^-5 s from the point of view of the observer.
The equation for time dilation is:

Then:

From the point of view of the moun Earth moved at 0.983c (2.949*10^8 m/s) during a time of 2.198*10^-6, so it moved
d = v*t = 2.949*10^8 * 2.198*10^-6 = 648 m