Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is option 3
Explanation:
From the question we are told that
The diameter of solenoid 1 is 
The length of solenoid 1 is 
The number of turns of solenoid is 
The diameter of solenoid 2 is 
The length of solenoid 2 is 
The number of turns of solenoid 2 is 
Generally the magnetic in a solenoid is mathematically represented as

From this equation we see that


Here C stands for constant
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<span>Let m1=10kg and m2=5kg and for our calculations assume right is positive and up is positive (note: for block hanging, the x axis is vertical so tilt your head to help)
For m1
Sigma Fx = ma
T - m1gsin35 = m1a where T = tension
For m2
m2g - T = m2a
Add equation together
m1a + m2a = T-m1gsin35 + m2g - T
a(m1 + m2) = m2g - m1gsin35
a= (5*9.8 - 10*9.8*sin35)/(10 + 5)
a= -0.48m/s/s
So the system is moving in the opposite direction of our set coordinate system where we said right positive, its negative so its moving left therefore down the ramp</span>
Answer: Change in ball's momentum is 1.5 kg-m/s.
Explanation: It is given that,
Mass of the ball, m = 0.15 kg
Speed before the impact, u = 6.5 m/s
Speed after the impact, v = -3.5 m/s (as it will rebound)
We need to find the change in the magnitude of the ball's momentum. It is given by :
So, the change in the ball's momentum is 1.5 kg-m/s. Hence, this is the required solution.
Read more on Brainly.com - brainly.com/question/12946012#readmore
Answer:
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
Explanation:
We must work on this problem using the rotational equilibrium equations and then they compared the tension values that the cable supports.
Let's start with fixing a reference system on the hinge of the flag, we take as positive the anti-clockwise turn
They indicate the weight of the pole W₁ = 120 lb and a length of L = 9 ft, the weight of the man W₂ = 150, we assume that the cable is at the tip of the pole
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L + W₂ L + W₁ L / 2 = 0
T_{y} = W₂ + W₁ / 2
T_{y} = 120 + 150/2
T_{y} = 195 lb
we use trigonometry to find the cable tension
sin 30 = T_{y} / T
T = T_{y} / sin 30
T = 195 / sin 30
T = 390 lb
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
T < 500 lb