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Thepotemich [5.8K]
2 years ago
9

A pizza delivery driver must make three stops on her route. She will first leave the restaurant and travel 4 km due north to the

first house. The next house is 6 km away at 45° south of west according to her map. The final stop is 5 km away at 60° north of west. What is her displacement from the restaurant to the final stop?
Physics
1 answer:
topjm [15]2 years ago
4 0
<h2>5.3 km</h2>

Explanation:

       This question involves continuous displacement in various directions. When it becomes difficult to imagine, vector analysis becomes handy.

       Let us denote each of the individual displacements by a vector. Consider the unit vectors \vec{i}\textrm{ and }\vec{j} as the unit vectors in the direction of East and North respectively.

       By simple calculations, we can derive the unit vectors \vec{j},\frac{-\vec{i}-\vec{j}}{2}\textrm{ and }\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2} in the directions North, 45^{o} South of West and 60^{o} North of West respectively.

       So Total displacement vector = Sum of individual displacement vectors.

       Displacement vector = 4(\vec{j})+6(\frac{-\vec{i}-\vec{j}}{2})+5(\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2})=-4.25\vec{i}+3.165\vec{j}

       Magnitude of Displacement = |-4.25\vec{i}+3.165\vec{j}|=5.3km

∴ Total displacement = 5.3km

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VladimirAG [237]

Answer:

W=1259W=1.2Kw

Explanation:

Hello!

The first step to solve is to find the enthalpies at the entrance (state 1) and the exit of the washer, for this we use the thermodynamic tables.

Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  

state 1

h1(T=20C,P=1atm)=83.93kJ/kg

state 2

h1(T=23C,P=1atm)=96.48kJ/kg

now we find the mass flow remembering that it is the product of the flow rate by the density=

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M=\alpha q

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α=Density=1000kg/m^3

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mh1+W+\frac{v1^2}{2g} =0.1W+mh2+\frac{v2^2}{2g}+mgH

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h=entalpy

v=speed

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W=\frac{m2h2-m1h1+m\frac{v2^2-v1^2}{g}+mgH}{1.1}

W=\frac{(0.1)(96480)-(0.1)(83930)+\frac{0.1(50^2-0.2^2)}{2}+0.1(9.81)(5)}{1.1}

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Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish
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Answer:

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

Explanation:

This exercise can be analyzed with the law of refraction that establishes that a ray of light when passing from one medium to another with a different index makes it deviate from its path,

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where n₁ and n₂ are the refractive indices of the incident and refracted means and the angles are also for these two means.

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

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