The efficiency of the first Carnot engine is
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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Putting together two distinct 50 dB sound, do not create a 100 dB sound. Since decibels are logarithm of energy, creating two sounds together only makes the energy increase but the logarithm only goes up by somehow little. So increasing the sound by 10 dB, only makes it 10000 times louder because each 10 dB increase in sound makes the sound 10 times louder.
Twice as loud is an increase of 10Log (2) = 3.01 dB. So, 53,01 dB is twice as loud as 50dB.
A. The horizontal velocity is
vx = dx/dt = π - 4πsin (4πt + π/2)
vx = π - 4π sin (0 + π/2)
vx = π - 4π (1)
vx = -3π
b. vy = 4π cos (4πt + π/2)
vy = 0
c. m = sin(4πt + π/2) / [<span>πt + cos(4πt + π/2)]
d. m = </span>sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]
e. t = -1.0
f. t = -0.35
g. Solve for t
vx = π - 4πsin (4πt + π/2) = 0
Then substitute back to solve for vxmax
h. Solve for t
vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax
i. s(t) = [<span>x(t)^2 + y</span>(t)^2]^(1/2)
h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt
k and l. Solve for the values of t
d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to determine the maximum and minimum speeds.
<span>High SchoolPhysics5+3 pts</span><span>Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each term with its definition. Tiles conductor radiation insulator convection conduction Pairs heat transfer involving direct contact of particles arrowBoth heat transfer in fluids arrowBoth heat transfer that doesn’t need a medium arrowBoth substance that doesn’t allow heat through arrowBoth substance that allows heat through arrowBoth
These are the answers:
</span>Conductor - <span>substance that allows heat through
</span>Radiation - <span> heat transfer that doesn’t need a medium
</span>Insulator - <span>substance that doesn’t allow heat through
</span>Convection - <span>heat transfer in fluids
Conduction - </span>heat transfer involving direct contact of particles
Answer:
<h3>0.99 m</h3>
Explanation:
Average velocity is the change of rate of displacement with respect to time;
Average velocity = Displacement/Time
Given
Average velocity of the frog = 1.8m/s
Time = 0.55s
Required
Displacement of the frog
Substitute the given parameters into the formula;
1.8 = displacement/0.55
cross multiply
Displacement = 1.8*0.55
Displacement = 0.99 m
Hence the frog's displacement is 0.99m
