Answer:
252.45 hours or 908820 seconds
Explanation:
The equatorial radius of Saturn is 60,268 km
The length of the equator will be circumference
Speed of the equatorial flow = 1500 km/h
It will take 252.45 hours or 908820 seconds for the equatorial flow to encircle the planet.
Answer:
Mobility of the minority carriers,
Diffusion coefficient for minority carriers,
Verified from Einstein relation as
Explanation:
Length of sample,
Separation between the two probes, L = 1.8 cm
Drift time,
Applied voltage, V = 5 V
Mobility of the minority carriers ( electrons),
Where the drift velocity,
and the Electric field strength,
E = 5/2
E = 2.5 V/cm
Mobility of the minority carriers:
The electron diffusion coefficient,
, where Δt = separation of pulse seen in an oscilloscope in time( it should be in micro second range)
For the Einstein equation to be satisfied,
Verified.
Answer:
Option B, 93 cm
Explanation:
An diagram of the seed's motion is attached to this solution.
This is very close to a projectile motion question. And the quantity to be calculated, how far along the grant a seed released would travel is called the Range.
And this would be obtained from the equations of motion,
First of, the height of the plant is related to some quantities of the motion with this relation.
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s, H = height at which motion began, = 20cm = 0.2 m
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t + 0.5g(t^2) = u(x) t (the second part of the equation goes to zero as the vertical component of the acceleration of this motion is 0)
(substituting the t = √(2H/g) derived from above
R = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = maximum initial speed, that is, 4.6 m/s, H = vertical height at which the seed was released = 20 cm = 0.2 m, g = acceleration due to gravity = 9.8 m/s2
R = 4.6 √(2×0.2/9.8) = 0.929 m = 0.93 m = 93 cm. Option B.
QED!
