Find the mass of a person walking west at a speed of 0.8 m/s with a momentum of 52.0 kg.m/s west.
1 answer:
Answer:
mass of the person walking to west is 65 kg.
Given:
Momentum = 52
Speed = 0.8
To find:
Mass of the person = ?
Formula used:
Momentum is given by,
P = m × v
Where, P = momentum
m = mass
v = speed
Solution:
Momentum is given by,
P = m × v
Where, P = momentum
m = mass
v = speed
Mass =
m =
m = 65 kg
Thus, mass of the person walking to west is 65 kg.
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Answer:
W = 506.75 N
Explanation:
tension = 2300 N
Rider is towed at a constant speed means there no net force acting on the rider.
hence taking all the horizontal force and vertical force in consideration.
net horizontal force:
F cos 30° - T cos 19° = 0
F cos 30° = 2300 × cos 19°
F = 2511.12 N
net vertical force:
F sin 30° - T sin 19°- W = 0
W = F sin 30° - T sin 19°
W = 2511.12 sin 30° - 2300 sin 19°
W = 506.75 N
The correct answer to the question is : 29.88 m.
EXPLANATION :
As per the question, the mass of the rock m = 50 Kg.
The rock is rolling off the edges of the cliff.
The final velocity of the rock when it hits the ground v = 24 .2 m/s.
Let the height of the cliff is h.
The potential energy gained by the rock at the top of the cliff = mgh.
Here, g is known as acceleration due to gravity, and g =
When the rock rolls off the edge of the cliff, the potential energy is converted into kinetic energy.
When the rock hits the ground, whole of its potential energy is converted into its kinetic energy.
The kinetic energy of the rock when it touches the ground is given as -
Kinetic energy K.E = .
From above we know that -
Kinetic energy at the bottom of the cliff = potential energy at a height h
⇒
⇒
⇒
⇒
Hence, the height of the cliff is 29.88 m