Answer:
A. Ahmed has a greater tangential speed than Jacques.
D. Jacques and Ahmed have the same angular speed.
Explanation:
Kinematics of the merry-go-round
The tangential speed of the merry-go-round is calculated using the following formula:
v = ω*R
Where:
v is the tangential speed in meters/second (m/s)
ω is the angular speed in radians/second (rad/s)
R is the angular speed in meters (m)
Data
dA = RA : Ahmed distance to the axis of rotation
dJ = RJ : Jacques distance to the axis of rotation
Problem development
We apply the formula (1)
v = ω*R
vA= ω*RA : Ahmed tangential speed
vJ= ω*RJ : Jacques tangential speed
Ahmed is at a greater distance from the axis of rotation than Jacques, then,
RA ˃ RJ and Ahmed and Jacques have the same speed ω, then:
vA ˃ vJ
Answer: 1.9m
Explanation:
60 cm x 22/7 x 10cm = 1.9m
Answer:
A. the wave speed v and Wavelength
Explanation:
Given that
Mass density per unit length=μ
Frequency = f
The velocity V given as


T=Tension
V=Velocity
V= f λ
λ=Wavelength
Therefore to find the tension ,only wavelength and speed is required.
The answer is A.
I can't seem to figure out the angle between T1 and T2. So suppose, it is 10º; then T2 makes an angle of 35º w/r/t horizontal, and T1 makes an angle of 45º.
Sum the moments about the base of the crane; Σ M = 0. 0 = T2*cos35*L*cos40 + T1*cos45*L*cos40 - T2*sin35*L*sin40 - T1*sin45*L*sin40 - W*(L/2)*sin40 - T1*L*sin40 → length L cancels where W = 18 kN
0 = 0.259*T2 - 43kN T2 = 166 kN
<em>If the distance between the two objects is the same, then;</em>
Both the magnet and the coil moving toward each other at 10 cm/s each
A reversed polarity magnet moving away from the coil at 20 cm/s
<u>Calculate current that produces a magnetic field, and use the right hand rule 2, to determine the direction of current or the direction of magnetic field loops. </u>