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Ymorist [56]
2 years ago
10

robby skateboards 0.50 blocks to his friend's house in 1.2 minutes. what is his speed? 6.0 blocks/min 6.0 blocks/min, in the dir

ection of his friend's house 0.42 blocks/min 0.42 blocks/min, in the direction of his friend's house
Physics
2 answers:
Annette [7]2 years ago
4 0
That would be 0.42 blocks per minute 
tatiyna2 years ago
3 0

Answer: The speed of the Robby was 0.42 blocks/min.

Explanation:

Distance covered by Robby = 0.50 blocks

Time taken by Robby = 1.2 minutes

Speed of the Robby = \frac{Distance}{time}=\frac{0.50 blocks}{1.2 min}=0.41666 blocks/minutes\approx 0.42 blocks/minutes

The Robby's speed was 0.42 blocks/min.

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An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th
stepan [7]

Answer:

Number of photons travel through pin hole=6.4*10^{17}

Explanation:

First we will calculate the energy of single photon using below formula:

E=\frac{h*c}{λ}

Where :

h is plank's constant with value 6.626*10^{-34} J.s

c is the speed of light whch is3*10^{8}

λ is the wave length = 532nm

E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}

E=3.73*10^{-19}J

Number of photons emitted per second:

\frac{5J/s}{1 photon/3.73*10^{-19} }

Number of photons emitted per second=1.34*10^{19} photons/s

\frac{A-hole}{A-beam}=\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

\frac{A-hole}{A-beam}=\frac{d-hole^2}{d-beam^2}

\frac{Ahole}{A-beam}=\frac{1.22^2}{5.5^2}

\frac{A-hole}{A-beam}=\frac{144}{3025}

Number of photons travel through pin hole=1.34*10^{19} *\frac{144}{3025}

Number of photons travel through pin hole=6.4*10^{17}

7 0
2 years ago
As you know, loudspeakers are used for communication at sporting events, and in schools or supermarkets. Research loudspeakers o
Ivahew [28]

Sound is invisible, but sometimes we can feel it. when a kettle-drum is thumped with a stick that time the tight drum skin moving up and down very quickly for some time and then it pumped sound waves into the air. Loudspeakers also work in a similar manner.

components of a speaker:

Electromagnet

In order to translate an electrical signal into an audible sound, an electromagnet is used in looudspeakers

 Suspension

suspension is used to  center the voice coil in the gap of the magnet and it exerts a restoring force to keep it there. suspension is used to limits the maximum mechanical excursion of the diaphragm and voice coil.

voice Coil

Voice coil is a coil of wire which is attached to the apex of a loudspeaker cone. It provides the motive force to the cone by the reaction of a magnetic field to the current passing through it.

Cone

In a  loudspeaker, a  thin, semi-rigid membrane attached to the voice coil, which moves in a magnetic gap due to which it vibrates  and produced sound. It is known as diaphragm and It can also be called a cone, though not all speaker diaphragms are cone-shaped.

Surround

surround is also known as front suspension. surround is used to join the cone to the chassis. Together with the suspension it controls the cone excursion, and it is also used to  determine how energy which is  travelling through the cone is absorbed, and how the speaker limits when it reaches the ends of its travel.

Dustcap

dustcap is used to protect the voice coil from dust and dirt. It is a part of the cone.

How speaker work

The outer part of the cone is fastened to the outer part of the loudspeaker's circular metal rim. The inner part is fixed to  voice coil that sits just in front of a permanent magnet . When loudspeaker is hooked up to a stereo, electrical signals feed through the speaker cables into the coil. It will convert the coil into an electromagnet magnet . when electricity flows back and forth in the cables, the electromagnet either repels or attract the permanent magnet. This moves the coil back and forth, and it pull and push the loudspeaker cone. Like a drum skin vibrating back and forth, the moving cone pumps sounds out into the air.In this way loudspeakers works.

4 0
2 years ago
A hockey puck of mass m1=165 g slides from left to right with an initial velocity of 15.5 m/s. It collides head on with a second
Fynjy0 [20]

Answer:

it may be -6 m/s

Explanation:

3 0
2 years ago
A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr
Harlamova29_29 [7]

Answer:

a) m = 3 for λ1 and m= 2 for λ2 will overlap since they have the same values

b) At what angle does this overlap occur = 34.54 degree

Explanation:

The detailed steps and appropriate formula is as shown in the attachment.

8 0
2 years ago
A cubical shell with edges of length a is positioned so that two adjacent sides of one face are coincident with the +x and +y ax
Bingel [31]

Answer:

Q = ba⁴ * ε₀

Explanation:

From Gauss's Law, we know that

flux Φ = Q / ε₀

where ε₀ = 8.85e-12 C²/N·m²

and also,

Φ = EAcosθ

The field is directed along the x-axis, so that all of the flux passes through the side of the cube at x = a. This means that θ = 0º, and thus

Φ = EAcos0

Φ = EA

E = bx² meanwhile, we are interested in the point where x = a, so we substitute and then

E = ba²

Since A = a² for the cube face, we have

Q / ε₀ = E * A

Q / ε₀ = ba² * a²

so that

Q = ba⁴ * ε₀

5 0
2 years ago
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