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Kamila [148]
2 years ago
5

As a 5.0 x 10^2 newton basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on th

e floor is 1.0 x 10^3 newtons. As she jumps, the magnitude of the force of the floor on her feet is
1) 5.0 x 10^2 N
2) 1.0 x 10^3 N
3) 1.5 x 10^3 N
4) 5.0 x 10^5 N
Physics
2 answers:
Harlamova29_29 [7]2 years ago
5 0

Answer:

2) 1.0 x 10^3 N

Explanation:

As a 5.0 x 10^2 newton basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floor is 1.0 x 10^3 newtons. As she jumps, the magnitude of the force of the floor on her feet is

1) 5.0 x 10^2 N

2) 1.0 x 10^3 N

3) 1.5 x 10^3 N

4) 5.0 x 10^5 N

The answer is B , because from newton's third law of motion which states that action and reaction are equal and opposite.

so the reaction of the floor on her leg will be equal to the the magnitude of her feet on the floor, this will hold if the floor does not collapse.

Yuliya22 [10]2 years ago
4 0
I believe the answer is (4) The reason that is, is because if the exponents are the same like 10^2 and 10^3, you can add them. Then you would get 10^5. You can go ahead though and multiply 5.0 and 1.0. Now remember that with decimals you don't need the zeros behind the decimal point. So that simplifies it with just 5 x 1. Leaving you with 5.0 x 10^5. 
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avanturin [10]

6m at 0.9 radian means 6m at 51.57^0

Since positive angles are counter clockwise

6m at 51.57^0 can be written as 6*cos51.57^0i+6*sin51.57^0j = 3.73i+4.70j

5m at -75^0 can be written as 5*cos(-75)^0i+5*sin(-75)^0j = 1.294i-4.83j

4m at 1.2 radian means 4m at 68.75^0

4m at 68.75^0 can be written as 4*cos68.75^0i+4*sin68.75^0j = 1.45i+3.73j

6m at -210^0 can be written as 6*cos(-210)^0i+6*sin(-210)^0j = -5.20i-3j

a) So sum of the vector = 1.274i+0.6j

b) Magnitude = \sqrt{1.274^2+0.6^2} = 1.98 m

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7 0
1 year ago
A metal has a strength of 414 MPa at its elastic limit and the strain at that point is 0.002. Assume the test specimen is 12.8-m
ser-zykov [4K]

To solve this problem, we will start by defining each of the variables given and proceed to find the modulus of elasticity of the object. We will calculate the deformation per unit of elastic volume and finally we will calculate the net energy of the system. Let's start defining the variables

Yield Strength of the metal specimen

S_{el} = 414Mpa

Yield Strain of the Specimen

\epsilon_{el} = 0.002

Diameter of the test-specimen

d_0 = 12.8mm

Gage length of the Specimen

L_0 = 50mm

Modulus of elasticity

E = \frac{S_{el}}{\epsilon_{el}}

E = \frac{414Mpa}{0.002}

E = 207Gpa

Strain energy per unit volume at the elastic limit is

U'_{el} = \frac{1}{2} S_{el} \cdot \epsilon_{el}

U'_{el} = \frac{1}{2} (414)(0.002)

U'_{el} = 414kN\cdot m/m^3

Considering that the net strain energy of the sample is

U_{el} = U_{el}' \cdot (\text{Volume of sample})

U_{el} =  U_{el}'(\frac{\pi d_0^2}{4})(L_0)

U_{el} = (414)(\frac{\pi*0.0128^2}{4}) (50*10^{-3})

U_{el} = 2.663N\cdot m

Therefore the net strain energy of the sample is 2.663N\codt m

6 0
1 year ago
A 74.9 kg person sits at rest on an icy pond holding a 2.44 kg physics book. he throws the physics book west at 8.25 m/s. what i
never [62]

Answer:

The recoil velocity is 0.2687 m/s.

Explanation:

∵ The person is sitting on an icy surface , we can assume that the surface is frictionless.

∴ There is no force acting acting on the person and book as a system in horizontal direction.

Hence , momentum is conserved for this system in horizontal direction of motion.

If 'i' and 'f' be the initial and final states of this system , then by principle of conservation of momentum(p)  -

p_{i}=p_{f}

System initially is at rest

∴p_{i}=0

∴ From the above 2 equations

p_{f}=0

We know that ,

Momentum(p)=Mass of the body(m)×velocity of the body(v)

Let m_{1} and m_{2} be the mass of the person and the book respectively and v_{1} and v_{2} be the final velocities of the person and book respectively.

∴p_{f}=m_{1}v_{1}+m_{2}v_{2}=0

From the question ,

m_{1} = 74.9 kg

m_{2} = 2.44 kg

v_{2} = 8.25 m/s

Substituting these values in the above equation we get ,

(74.9 × v_{1} )+ (2.44×8.25) = 0

∴v_{1}  = - 0.2687 m/s (Negative sign suggests that the motion of  the person is opposite to that of the book)

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4 0
2 years ago
The bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7 kg, what is its kinetic energy
Lisa [10]
Kinetic Energy = 1/2xmassx(velocity)^2
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3 0
2 years ago
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matrenka [14]

Answer:

42 degrees, virtual image, same size as the object (26 cm)

Explanation:

The law of reflection states that:

- When a ray of light is incident on a flat surface (such as the plane mirror), the angle of reflection is equal to the angle of incidence

So, since in this case the angle of incidence is 42 degrees, the angle of reflection is also 42 degrees.

Moreover, the image formed by a plane mirror is always:

- Virtual (on the same side as the object)

- The same size as the object

So in this case, since the object's size is 26 cm, the image's size is also 26 cm.

8 0
2 years ago
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