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pentagon [3]
2 years ago
11

Rod A has twice the diameter of rod B, but both are made of iron and have the same initial length. Both rods are now subjected t

o the same change in temperature (but remain solid). How would the change in the rods' lengths compare
Physics
1 answer:
Vilka [71]2 years ago
4 0

Answer:

ΔLa/ΔLb = 1

Explanation:

The change in length of a solid is given by the following formula:

ΔL = α L ΔT

where,

ΔL = Change in length

α = coefficient of linear expansion

L = Original Length

ΔT = Change in Temperature

Since, the length and change in temperature for both rods are same. Also, the material of each rod is same, which implies that coefficient of linear expansion for both rods is same. Hence, the ratio of change in length of both rods will be:

<u>ΔLa/ΔLb = 1</u>

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A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of
adelina 88 [10]

Answer:

x = 11.23  m

Explanation:

For this interesting exercise, we must use angular kinematics, linear kinematics and the relationship between angular and linear quantities.

Let's reduce to SI system units

    θ = 155 rev (2pi rad / rev) = 310π rad

    α = 2.00rev / s2 (2pi rad / 1 rev) = 4π rad / s²

Let's look for the angular velocity at the time the piece is released, with starting from rest the initial angular velocity is zero (wo = 0)

    w² = w₀² + 2 α θ  

    w =√ 2 α θ

    w = √(2 4pi 310pi)

    w = 156.45  rad / s

The relationship between angular and linear velocity

    v = w r

    v = 156.45  0.175

    v = 27.38 m / s

In this part we have the linear speed and the height that it travels to reach the floor, so with the projectile launch equations we can find the time it takes to arrive

    y = v_{oy} t - ½ g t²

As it leaves the highest point its speed is horizontal

   y = 0 - ½ g t²

   t = √ (-2y / g)

   t = √ (-2 (-0.820) /9.8)

   t = 0.41 s

With this time we calculate the horizontal distance, because the constant horizontal speed

   x = vox t

   x = 27.38 0.41

   x = 11.23  m

5 0
2 years ago
An ideal gas at temperature t0 is slowly compressed at constant pressure of 2 atm from a volume of 10 liters to a volume of 2 li
Sati [7]
<span>Answer: 1600 J

Explanation:

1) Data:

a) ideal gas: ⇒ pV = nRT and work = ∫ pdV
b) slowly compressed ⇒ constant temperature and not heat exchange
c) pressure: p =  2 atm
d) intitial volume: Vi = 10 liters
e) final volumen: Vf = 2 liters.
f) then the volume of the gas is held constant ⇒ not work in this stage.
g) calculate the work done on the gas: W = ?

2) Equation

W = ∫pdV

3) Solution:

Since p = constant,  W = p ∫dV = p ΔV = p (Vf - Vi)

p = 2 atm × 1.0 ×10⁵ Pa / atm = 200.000 Pa

Vi = 10 liter ×  0.001 m³ ./ liter = 0.01 m³

Vf = 2 liter × 0.001 m³ / liter = 0.002 m³

W = 200.000 Pa × (0.002 m³ - 0.01m³) = - 1.600 J.

The negative sign means the work is done over the system.

That is all the work in the system because at the second stage the volume is held constant.
</span>
8 0
2 years ago
Which describes a grizzly bear’s habitat? all the biotic factors in the ecosystem all the abiotic factors in the ecosystem the r
Talja [164]

Answer:

I found this question elsewhere on brainly and the answer was verified. Here it is!

Explanation:

Grizzly bear habitats is the habitat or the physical space where the bear lives. Grizzly bears can be found in many different habitats from dense forests to subalpine meadows, arctic tundra and open plains. We can also conclude that all of the bears live in grizzly bear's habitat in order to survive.

3 0
2 years ago
Read 2 more answers
Suppose the value of one division of vernier scale is 0.5mm and the value of one main scale
gregori [183]

Answer:

-0.01 mm

Explanation:

We are given that

The value of one division of vernier scale =0.5 mm

The value of one main scale division=0.49 mm

We have to find the value of least count of the instrument in mm.

We know that

Leas count of vernier caliper=1 main scale division-1 vernier scale division

Least count of vernier caliper=0.49-0.50=-0.01 mm

Hence, the least count of the instrument=-0.01 mm

Answer: -0.01 mm

8 0
2 years ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23
Burka [1]

Answer:

a) v(2) = 3.9\,\frac{m}{s}, b) v(4) = -15.7\,\frac{m}{s}

Explanation:

a) The equation for vertical velocity is obtained by deriving the function with respect to time:

v(t) = 23.5 -9.8\cdot t

The velocities at given instants are, respectivelly:

v(2) = 3.9\,\frac{m}{s}

v(4) = -15.7\,\frac{m}{s}

8 0
2 years ago
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