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NeTakaya
2 years ago
6

As a blacksmith heats a piece of iron, the iron glows red, then yellow, then white. The iron provides a demonstration of which p

henomenon?
A. Emission spectra

B. Quantum mechanics

C. Photoelectric effect

D. Blackbody radiation
Physics
1 answer:
Nitella [24]2 years ago
6 0
The answer is D. Blackbody radiation. The piece of iron glows red because its temperature is around 1000 K, then yellow because its temperature is around 2800 K, and then white because its temperature is around 5500K. This shows that the spectrum of the radiation is determined by absolute temperature, as when the temperature of a blackbody radiator increases, the peak of the radiation curve moves to shorter wavelengths. 
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Interference occurs with not only light waves but also all frequencies of electromagnetic waves and all other types of waves, su
telo118 [61]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

4 0
2 years ago
A 74.9 kg person sits at rest on an icy pond holding a 2.44 kg physics book. he throws the physics book west at 8.25 m/s. what i
never [62]

Answer:

The recoil velocity is 0.2687 m/s.

Explanation:

∵ The person is sitting on an icy surface , we can assume that the surface is frictionless.

∴ There is no force acting acting on the person and book as a system in horizontal direction.

Hence , momentum is conserved for this system in horizontal direction of motion.

If 'i' and 'f' be the initial and final states of this system , then by principle of conservation of momentum(p)  -

p_{i}=p_{f}

System initially is at rest

∴p_{i}=0

∴ From the above 2 equations

p_{f}=0

We know that ,

Momentum(p)=Mass of the body(m)×velocity of the body(v)

Let m_{1} and m_{2} be the mass of the person and the book respectively and v_{1} and v_{2} be the final velocities of the person and book respectively.

∴p_{f}=m_{1}v_{1}+m_{2}v_{2}=0

From the question ,

m_{1} = 74.9 kg

m_{2} = 2.44 kg

v_{2} = 8.25 m/s

Substituting these values in the above equation we get ,

(74.9 × v_{1} )+ (2.44×8.25) = 0

∴v_{1}  = - 0.2687 m/s (Negative sign suggests that the motion of  the person is opposite to that of the book)

∴ The recoil velocity is 0.2687 m/s.

4 0
2 years ago
A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 46 %
olasank [31]

Answer:

height is 69.68 m

Explanation:

given data

before it hits the ground =  46 % of entire distance

to find out

the height

solution

we know here acceleration and displacement that is

d = (0.5)gt²     ..............1

here d is distance and g is  acceleration and t is time

so when object falling it will be

h = 4.9 t²   ....................2

and in 1st part of question

we have (100% - 46% ) = 54 %

so falling objects will be there

0.54 h = 4.9 (t-1)²       ...................3

so

now we have 2 equation with unknown

we equate both equation

1st equation already solve for h

substitute h in the second equation and find t

0.54 × 4.9 t² = 4.9 (t-1)²  

t = 0.576 s and  3.771 s

we use here 3.771 s because  0.576 s is useless displacement in the last second before it hits the ground is 46 % of the entire distance it falls

so take t = 3.771 s

then h from equation 2

h = 4.9 t²

h = 4.9 (3.771)²

h =  69.68 m

so height is 69.68 m

6 0
2 years ago
Identify whether the features and functions belong to the Hubble Space Telescope or the ALMA radio telescope. 1.installed on lan
tester [92]
Hublle Space Telescope
- Orbits around  Earth.
- Receive light before it enters Earth's Atmosphere. 
- Get information about stars before they are born.

Alma Radio Telescope
- Installed on land.
- Receive light after it passes through Earth's Atmosphere.
- Get information about stars after they are born. 

5 0
2 years ago
Read 2 more answers
8. Rubbing a plastic bag and a balloon with a cloth gives both objects a net negative charge. The balloon's
Dafna1 [17]

Answer:

0.214 m

Explanation:

In order for the bag to levitate and not fall down, the electrostatic force between the bag and the balloon must balance the weight of the bag.

Therefore, we can write:

k\frac{q_1 q_2}{r^2}=mg

where

k is the Coulomb constant

q_1=-1\cdot 10^{-10}C is the charge on the balloon

q_2=-1\cdot 10^{-5} C is the charge on the bag

r is the separation betwen the bag and the balloon

m=0.02 g=2\cdot 10^{-5} kg is the mass of the bag

g=9.8 m/s^2 is the acceleration due to gravity

Solving for r, we find the distance at which the bag must be held:

r=\sqrt{\frac{kq_1 q_2}{mg}}=\sqrt{\frac{(9\cdot 10^9)(-1\cdot 10^{-10})(-1\cdot 10^{-5})}{(2\cdot 10^{-5})(9.8)}}=0.214 m

5 0
2 years ago
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