Question

A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the distance the car travels during this time.

Answer 1

It traveled 39.6 meters

Answer 2

Answer:

Distance covered by the car, s = 21.56 meters

Explanation:

Given that,

Initially, the car is at rest, u = 0

It reaches a speed, final speed, v = 6.6 m/s

Time, t = 6.5 s

We need to find the distance covered by the car during this time. Firstly, we can find the acceleration of the car using equation of motion as :

$v=u+at$

$6.6=0+a\times 6.5$

$a=1.01\ m/s^2$

Now using third equation of motion to find distance (s) as :

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{(6.6)^2}{2\times 1.01}$

s = 21.56 meters

So, the distance traveled by the car during 6.5 seconds is 21.56 meters. Hence, this is the required solution.