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ololo11 [35]
2 years ago
5

A 16-kg scooter is moving at a speed of 7 m/s. The scooter’s speed doubles. What is the scooter’s kinetic energy when its speed

doubles?
a. 784 J
b. 1568 J
c. 392 J
d. 112 J
Physics
1 answer:
lbvjy [14]2 years ago
5 0
The formula for kinetic energy is:

KE = 0.5mv^2

where:
m = mass
v = speed

Given this formula, the original KE of the scooter is calculated as 392 J. Since the speed is doubled, it can be observed in the formula that the change would actually affect the kinetic energy by quadrupling it. This is because 2^2 is 4. So, 392(4) = 1568 J or B.
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kvasek [131]

Answer:

First Question

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Second  Question

   The  wavelength is for an X-ray  

Explanation:

From the question we are told that

     The  width of the wall is  w =  10\ fm =  10*10^{-15 }\ m

     The  first excited state is  n_1  =  2

     The  ground state is   n_0 = 1

Gnerally the  energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as

          E   =   \frac{h^2 }{ 8 * m  *  l^2 [ n_1^2 - n_0 ^2 ] }

Here  h is the Planck's constant with value  h =  6.62607015 * 10^{-34} J \cdot s

         m is the mass of proton with value m  = 1.67 * 10^{-27} \   kg

So    

          E  =   \frac{( 6.626*10^{-34})^2 }{ 8 * (1.67 *10^{-27})  *  (10 *10^{-15})^2 [ 2^2 - 1 ^2 ] }

=>        E   =   1.065*10^{-12} \  J

Generally the energy of the photon emitted is also mathematically represented as

             E  =  \frac{h * c }{ \lambda }

=>          \lambda  =  \frac{h * c }{E }

=>          \lambda  =  \frac{6.62607015 * 10^{-34} * 3.0 *10^{8} }{ 1.065 *10^{-15 } }

=>         \lambda  =  1.87*10^{-10} \  m

Generally the range of wavelength of X-ray is  10^{-8} \to  1)^{-12}

So this wavelength is for an X-ray.

     

8 0
2 years ago
A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, take
Ad libitum [116K]

Answer:

F=(3i+3.6j)\ N

Explanation:

It is given that,

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Initial velocity of the puck, u=(1i+0j)\ m/s

After 8 seconds, final velocity of the puck, v=(6i+6j)\ m/s

Let the x and y component of force is given by F_x\ and\ F_y.

x component of force is given by :

F_x=m\times \dfrac{v-u}{t}

F_x=4.8\times \dfrac{6-1}{8}

F_x=3\ N

y component of force is given by :

F_y=m\times \dfrac{v-u}{t}

F_y=4.8\times \dfrac{6-0}{8}

F_y=3.6\ N

So, the component of the force is F=(3i+3.6j)\ N. Hence, this is the required solution.

7 0
2 years ago
A box with a mass of 100.0 kg slides down a ramp with a 50 degree angle. What is the weight of the box? N What is the value of t
nadya68 [22]

1) weight of the box: 980 N

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W=mg

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W=(100.0 kg)(9.8 m/s^2)=980 N


2) Normal force: 630 N

The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by

N=W cos \theta

where W is the weight of the box, calculated in the previous step, and \theta=50^{\circ} is the angle of the ramp. Substituting, we find

N=(980 N)(cos 50^{\circ})=630 N


3) Acceleration: 7.5 m/s^2

The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by

a_p = g sin \theta

Substituting, we find

W_p = (9.8 m/s^2)(sin 50^{\circ})=7.5 m/s^2

5 0
2 years ago
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Cloud [144]

Answer:

The ball reaches Barney  head in  t = 8 \ s

Explanation:

From the question we are told that

 The rise velocity is  v  =  14.70 \  m/s

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Generally from kinematic equation  

   s = ut + \frac{1}{2} gt^2

Here s is the distance of the object from Barney head ,

        u is the velocity of the object along the vertical axis which is equal but opposite to the velocity of the helicopter

So  

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So

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=  4.9 t^2 - 14.7t - 196 = 0

Solving the above equation using quadratic formula  

    The value of  t obtained is  t = 8 \ s

6 0
2 years ago
Weddell seals make holes in sea ice so that they can swim down to forage on the ocean floor below. Measurements for one seal sho
Mariulka [41]

Answer:

B. 1 m/s

Explanation:

Metric unit conversions:

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5 minutes = 5*60 = 300 seconds

So if a seal can reach a depth of 300m in a time of 300 seconds, its diving speed is the distance divided by time duration

v = s/t = 300/300 = 1m/s

So B is the correct answer

3 0
2 years ago
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