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Hunter-Best [27]
2 years ago
5

A fireman clings to a vertical ladder and directs the nozzle of a hose horizontally toward a burning building. The rate of water

flow is 6.31kg/s, and the nozzle speed is 12.5 m/s. The hose passes vertically between the fireman’s feet, which are 1.30 m below the nozzle. Choose the origin to be inside the hose between the fireman’s feet. What torque must the fireman exert on the hose? (This could also be stated, what is the rate of change of the angular momentum of the water?)
Physics
1 answer:
Aleks [24]2 years ago
4 0

Answer:

A torque of 102.5375 Nm must be exerted by the fireman

Explanation:

Given:

The rate of water flow = 6.31 kg/s

The speed of nozzle  = 12.5 m/s

Now, from the Newton's second law we have  

The reaction force to water being redirected horizontally (F) = rate of change of water's momentum in the horizontal direction

thus we have,

F = 6.31 kg/s x 12.5m/s

or

F = 78.875 N  

Now,

The torque (T) exerted by water force about the fireman's will be

T = (F x d)

or

T = 78.875 N x 1.30 m

T = 102.5375 Nm

hence,

<u>A torque of 102.5375 Nm must be exerted by the fireman</u>

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Answer:

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8 0
1 year ago
A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
jasenka [17]
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The sine ratio relates the y-component and the velocity by:

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Since you have the angle and the velocity and are asked by the x-component of the velocity, you need to use the cosine ratio:

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6 0
2 years ago
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The drawing shows a side view of a swimming pool. The pressure at the surface of the water is atmospheric pressure. The pressure
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Answer:

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Let's examine this equation in we see that the total pressure is directly proportional to the atmospheric pressure and depth

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7 0
2 years ago
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baherus [9]

Answer:

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and k/m is same for both the springs so they will oscillate at the same frequency.

hence option a is correct.

3 0
2 years ago
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