Answer:
a) m = 3 for λ1 and m= 2 for λ2 will overlap since they have the same values
b) At what angle does this overlap occur = 34.54 degree
Explanation:
The detailed steps and appropriate formula is as shown in the attachment.
Say the initial point is (0,0)
The final point is
x = 200 + 135*cos(30) = 200 + 135*sqrt(3)/2 = 316.91 ft
y = 135*sin(30) = 135/2 = 67.5 ft
Resultant vector = (316.91, 67.5) - (0,0) = 316.91, 67.5) ft
Answer: 70.5 km/h
Justification:
The question is not clearly stated but it seems you are asking for the x - component of the velocity of the helicopter.
You can find the x and y - components of the velocity using the trigonometric ratios sine and cosine.
The sine ratio relates the y-component and the velocity by:
sin(angle) = y-component of velocity / velocity
The cosine ratio related the x-component and the velocity by:
cos(angle) = x-component of velocity / velocity.
Since you have the angle and the velocity and are asked by the x-component of the velocity, you need to use the cosine ratio:
cos(35°)= x-component / 86.0 km/h
=> x -component = 86.0 km/h * cos(35°) = 70.5 km/h
Answer:
A) To true. he pressure at the bottom of the pool decreases by exactly the same amount as the atmospheric pressure decreases
Explanation:
Let us propose the solution of this problem before seeing the final statements. The pressure increases with the depth of raposin due to the weight of water that is above the person and also the pressure exerted by the atmosphere on the entire pool, the equation describing this process is
P =
+ ρ g y
Where
is the atmospheric pressure, ρ the water density, and 'y' the depth measured from the surface.
Let's examine this equation in we see that the total pressure is directly proportional to the atmospheric pressure and depth
Now we can examine the claims
A) To true. State agreement or with the equation above
B) False. Pressure changes with atmospheric pressure
C) False. It's the opposite
D) False. They are directly proportional
Answer:
a. Springs oscillate with the same frequency
Explanation:
As they both are in the same height at equilibrium, so
weight of ball must be balanced with spring force, that is
k×x=mg
k= stiffness constant of spring
x=distance stretched
g= acceleration due to gravity
so, we can write
k/m=g/x
as the g is a constant and they stretched to same distance x so the g/x term becomes constant and

and k/m is same for both the springs so they will oscillate at the same frequency.
hence option a is correct.