Answer:
The gravitational potential energy equals the work needed to lift the object.
Explanation:
here we know that

work done is given as

Potential energy is given as

force due to gravity is given as

now here if we plug in the value of distance and force in the formula of work done then we will have

so here we got

so we can concluded that
The gravitational potential energy equals the work needed to lift the object.
The question with the complete options:
Look at these two sentences about Undeposited Funds. 1. By posting to Undeposited Funds, you can create a single bank deposit for multiple payments, making it easy ___________. 2. When receiving a payment, make sure _________________. Which of the options below correctly fills in the blanks? A.)1. To match your bank register with your bank statement; 2. the Deposit to account is Undeposited Funds
B) 1. To match your bank register with your bank statement; 2. the Deposit to account is Checking
C)1. To match your expenses with your bank statement; 2. the Deposit to account is Uncategorized asset
D)1. To match your bank register with your bank statement; 2. the Deposit to account is Uncategorized funds.
Answer: The correct option is A (1. To match your bank register with your bank statement; 2. the Deposit to account is Undeposited Funds)
Explanation: Undeposited funds is a type of account created to keep funds that are not yet deposited in the individuals account. It's a default account which is used by online marketers to keep funds until they are ready to be paid.
By posting to Undeposited Funds, you can create a single bank deposit for multiple payments, making it easy to match your bank register with your bank statement. When receiving a payment, make sure the Deposit to account is Undeposited Funds.
.
Answer: 8.1 x 10^24
Explanation:
I(t) = (0.6 A) e^(-t/6 hr)
I'll leave out units for neatness: I(t) = 0.6e^(-t/6)
If t is in seconds then since 1hr = 3600s: I(t) = 0.6e^(-t/(6 x 3600) ).
For neatness let k = 1/(6x3600) = 4.63x10^-5, then:
I(t) = 0.6e^(-kt)
Providing t is in seconds, total charge Q in coulombs is
Q= ∫ I(t).dt evaluated from t=0 to t=∞.
Q = ∫(0.6e^(-kt)
= (0.6/-k)e^(-kt) evaluated from t=0 to t=∞.
= -(0.6/k)[e^-∞ - e^-0]
= -0.6/k[0 - 1]
= 0.6/k
= 0.6/(4.63x10^-5)
= 12958 C
Since the magnitude of the charge on an electron = 1.6x10⁻¹⁹ C, the number of electrons is 12958/(1.6x10^-19) = 8.1x10^24 to two significant figures.
Answer:
density is
Mg/µL
Explanation:
given data
density of nuclear =
kg/m³
1 ml = 1 cm³
to find out
density of nuclear matter in Mg/µL
solution
we know here
1 Mg = 1000 kg
so
1 m³ is equal to
cm³
and here 1 cm³ is equal to 1 mL
so we can say 1 mL is equal to 10³ µL
so by these we can convert density
density =
kg/m³
density =
kg/m³ ×
Mg/µL
density =
Mg/µL
Answer:
66.98 db
Explanation:
We know that

L_T= Total signal level in db
n= number of sources
L_S= signal level from signal source.

= 66.98 db