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brilliants [131]
2 years ago
12

The strength of intermolecular forces between particles affects physical properties of substances such as boiling point, melting

point, surface tension, and vapor pressure. Which substance has the highest melting point
A) C2H5O

B) C2H6

C) H2O

D) C6H6
Physics
2 answers:
Alexxx [7]2 years ago
7 0

Answer:

D) C6H6

Explanation:

The strength of intermolecular forces between particles affects physical properties of substances such as boiling point, melting point, surface tension, and vapor pressure. Which substance has the highest melting point

A) C2H5O

B) C2H6

C) H2O

D) C6H6

C2H5O has a melting point of -114.1^{0}c

C2H6  has a melting point of -182.8^{0}c

H2O has a melting point of 0^{0}c

c6h6 has a melting point of 5^{0}c

benzene as the highest melting point

When molecules are tightly packed together, a substance has a higher melting point than a substance with molecules that do not pack well. ... Molecular mass also affects the melting point. , smaller molecules melt at lower temperatures than larger molecules.

melting point is the temperature at which a substance coexist as both solid and liquid without any noticeable change in temperature

lara [203]2 years ago
5 0
The right answer is h2o


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An automobile approaches a barrier at a speed of 20 m/s along a level road. The driver locks the brakes at a distance of 50 m fr
AleksAgata [21]

Answer:

μ = 0.408

Explanation:

given,

speed of the automobile (u)= 20 m/s

distance = 50 m

final velocity  (v) = 0 m/s

kinetic friction = ?

we know that,

v² = u² + 2 a s

0 = 20² + 2 × a × 50

a = \dfrac{400}{2\times 50}

a = 4 m/s²

We know

F = ma = μN

ma = μ mg

a = μ g

\mu = \dfrac{a}{g}

\mu = \dfrac{4}{9.81}

μ = 0.408

hence, Kinetic friction require to stop the automobile before it hit barrier is 0.408

5 0
2 years ago
A flying mosquito hits the windshield of a moving car and gets smashed, but the car is intact. Which of the following statements
zhannawk [14.2K]

Answer:

Action and reaction are the same

Explanation:

Let us carefully analyze the situation in the context of Newton's third law, when the car hits the mosquito exerts a force that acts on the mosquito, ACTION and the mosquito responds to the force that is being applied with a force of equal magnitude and direction or opposite applied to the car (Reaction).

Consequently, the correct answer is: The force of the car on the mosquito is of the same magnitude as that of the mosquito on the car

6 0
2 years ago
You have two identical pure silver ingots. You place one of them in a glass of water and observe it to sink to the bottom. You p
Elis [28]

Answer: a)

Explanation:

The buoyant force, as stated by Archimedes’ principle, is equal to the weight of the liquid that occupies the same volumen as the submerged object, as follows:

Fb = δ.V.g

If this force is larger than the weight of the object (that means that the fluid is denser than the solid), the object floats, which is the case for silver and mercury.

Instead, silver density is larger than water density, which explains why the pure silver ingot sinks.

Finally, as mercury is denser than water, we conclude that for a same object, the buoyant force in mercury is larger than in water (exactly 13.6 times greater).  

3 0
2 years ago
A 2.70 kg cat is sitting on a windowsill. The cat is sleeping peacefully until a dog barks at him. Startled, the cat falls from
Alchen [17]

Answer:

The speed of the cat when it hits the ground is approximately 7.586 meters per second.

Explanation:

By Principle of Energy Conservation and Work-Energy Theorem, we have that initial potential gravitational energy of the cat (U_{g}), in joules, is equal to the sum of the final translational kinetic energy (K), in joules, and work losses due to air resistance (W_{l}), in joules:

U_{g} = K +W_{l} (1)

By definition of potential gravitational energy, translational kinetic energy and work, we expand the equation presented above:

m \cdot g\cdot h = \frac{1}{2}\cdot m \cdot v^{2}+W_{l} (2)

Where:

m - Mass of the cat, in kilograms.

g - Gravitational acceleration, in meters per square second.

h - Initial height of the cat, in meters.

v - Final speed of the cat, in meters per second.

If we know that m = 2.70\,kg, g = 9.807\,\frac{m}{s^{2}}, h = 5.20\,m and W_{l} = 120\,J, then the final speed of the cat is:

v = \sqrt{\frac{2\cdot (m\cdot g\cdot h-W_{l})}{m} }

v = \sqrt{2\cdot g\cdot h-\frac{W_{l}}{m} }

v \approx 7.586\,\frac{m}{s}

The speed of the cat when it hits the ground is approximately 7.586 meters per second.

4 0
2 years ago
Explain why the coin is able to float on top of the water in this glass
makkiz [27]

Explanation:

Becuse the coin has a <em><u>Lesser</u></em><em><u> </u></em><em><u>Density</u></em> than water.

3 0
1 year ago
Read 2 more answers
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