Answer:
19.99 kg m²/s
Explanation:
Angular Momentum (L) is defined as the product of the moment of Inertia (I) and angular velocity (w)
L = m r × v.
r and v are perpendicular to each other,
where r = lsinθ.
l = 2.4 m
θ= 34°
g = 9.8 m/s² and m = 5 kg
resolving using newtons second law in the vertical and horizontal components.
T cos θ − m g = 0
T sin θ − mw² lsin θ = 0
where T is the force with which the wire acts on the bob
w = √g / lcosθ
= √ 9.8 / 2.4 ×cos 34
= 2.2193 rad/s
the angular momentum L = mr× v
= mw (lsin θ)²
= 5 × 2.2193 (2.4 ×sin 34°)²
=19.99 kg m²/s
A complex entity involving the Earth's biosphere, atmosphere, oceans, and soil; the totality constituting a feedback or cybernetic system which seeks an optimal physical and chemical environment for life on this planet
Velocity =
(distance between start point and end point, regardless of the route traveled) / (time spent traveling).
That distance (called the "displacement"), is 10 meters, and almost exactly 1 hour is almost exactly 3,600 seconds. So the numerical value of the velocity during that time is
(10) / (3,600) = almost exactly 0.00278 m/s
= 2.78 x 10^-3 m/s.
We want to know the amount of force that stretches the spring 0.22 m.
That force is the WEIGHT of the mass hung from it.
The weight of the mass is (mass) times (gravity).
To do that calculation, we need to know the value of gravity, but
gravity has different values on every planet. I shall assume that
this whole springy question is taking place on Earth, so that the
value of gravity is 9.8 m/s² .
The weight of the mass is (0.4 kg) x (9.8 m/s²) = 3.92 Newtons.
The spring constant is
(force/length of the stretch)
= (3.92 Newtons) / (0.22 meters)
= (3.92 / 0.22) Newtons/meter
= 17.82 N/m .
