Answer:
The horizontal distance d does the ball travel before landing is 1.72 m.
Explanation:
Given that,
Height of ramp 
Height of bottom of ramp 
Diameter = 0.17 m
Suppose we need to calculate the horizontal distance d does the ball travel before landing?
We need to calculate the time
Using equation of motion




We need to calculate the velocity of the ball
Using formula of kinetic energy



Using conservation of energy



Put the value into the formula


We need to calculate the horizontal distance d does the ball travel before landing
Using formula of distance

Where. d = distance
t = time
v = velocity
Put the value into the formula


Hence, The horizontal distance d does the ball travel before landing is 1.72 m.
Answer:
the ratio is 
Explanation:
Given

The RMS velocity of molecules in a gas is given by

where T=temperature

For T = 387K

For T = 774

dividing eqn 1 and eqn 2


Thus,the ratio is 
Answer: 3 x 10^-24 watt
Explanation:
P ( resistivity) = 1.72e-8 (from the chart).
L= 2pi r
r= 30 cm.
R= pL/A
A= pi* r1^2
r1= 0.8118/2 * 10^-3 m
R= 1.68 x 10^-8 x (2x3.142x0.3)
= 3.24 x 10^-8
E=N do/dt
do= B* A
A= pi* 0.3^2
N=1
E = 1 x (14 x 3.142x 0.09) = 3.95
I=v/R
v=E,
I = 3.95 / 3.24 x 10^-8 = 1.22 x 10^8
P=I^2 x R.
= 3 x 10^-24 watt
R = 0.407Ω.
The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.
To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.
We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:
R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]
R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²
R = 0.407Ω