Answer:
a = 18.28 ft/s²
Explanation:
given,
time of force application, t= 10 s
Work = 10 Btu
mass of the object = 15 lb
acceleration, a = ? ft/s²
1 btu = 778.15 ft.lbf
10 btu = 7781.5 ft.lbf
m = 0.466 slug
now,
work done is equal to change in kinetic energy
now, acceleration of object
a = 18.28 ft/s²
constant acceleration of the object is equal to 18.28 ft/s²
Answer:
The level of the root beer is dropping at a rate of 0.08603 cm/s.
Explanation:
The volume of the cone is :
Where, V is the volume of the cone
r is the radius of the cone
h is the height of the cone
The ratio of the radius and the height remains constant in overall the cone.
Thus, given that, r = d / 2 = 10 / 2 cm = 5 cm
h = 13 cm
r / h = 5 / 13
r = {5 / 13} h
Also differentiating the expression of volume w.r.t. time as:
Given: = -4 cm³/sec (negative sign to show leaving)
h = 10 cm
So,
<u>The level of the root beer is dropping at a rate of 0.08603 cm/s.</u>