Answer:
The workdone is 
Explanation:
The free body diagram is shown on the first uploaded image
From the question we are given that
The force is on the force gauge 
The distance that Magnus pulled the bus 
Generally the workdone by the tension force on Magnus is
This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )
Substituting value we have
Answer:
Check the explanation
Explanation:
A) There are two important angles within the plastic: the angle immediately after the first refraction (the water/plastic interface) and the angle immediately before the second refraction (the plastic/air interface).
To find out how they relate, draw a picture with the path the light follows in the plastic and the normal to both surfaces.
Once you have labeled both angles, keep in mind that the surfaces are parallel, and thus their normal are parallel lines. An important theorem from geometry will give you the relationship between the angles.
Using Snell's Law, θa = asin[(nw/na)*sin(θw)]
B) D = l/tan(θw)
C) D = l/θw
D) d/D = na/nw
Answer:
<em>a) Fvt cosθ</em>
<em>b) Fv cosθ</em>
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Explanation:
Each horse exerts a force = F
the rope is inclined at an angle = θ
speed of each horse = v
a) In time t, the distance traveled d = speed x time
i.e d = v x t = vt
also, the resultant force = F cosθ
Work done W = force x distance
W = F cosθ x vt = <em>Fvt cosθ</em>
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b) Power provided by the horse P = force x speed
P = F cosθ x v
P = <em>Fv cosθ</em>
The correct answer would be that destructive interference is happening. In this interference, the crest of a wave meets a trough of another wave resulting to an amplitude that is lower. The opposite is called the constructive interference. Hope this answers the question.
