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2 years ago

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A bicyclist is riding at a tangential speed of 13.2 m/s around a circular track. The magnitude of the centripetal force is 377 N

, and the combined mass of the bicycle and rider is 86.5 kg. What is the track's radius?

1 answer:

MA_775_DIABLO [31]2 years ago

4 0

Answer:

40m approximately

Explanation:

Given

Force =377N

Mass =86.5kg

Velocity =13.2m/s

Required

Radius of the track

The expression for the centripetal force acting on the cyclist is

F=mv²/r

Make r subject of the formula

r= mv²/F

Substitute

r=86.5*13.2²/377

r= 15,071.76/377

r=39.97

r=40m approximately

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Heres the possible full question and solution:

A tank contains 100 gal of water and 50 oz of salt. Water containing a salt concentration of ¼ (1 + ½ sin t) oz/gal flows ito the tank at a rate of 2 gal/min, and the mixture in the tank flows out at the same rate.

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Assume that the amount of salt in the tank at time t is Q(t).

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Here, $\frac{dQ}{dt}$ =rate of liquid flowing in the tank - rate of liquid flowing out.

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$Rate_{in} =2gal/min \times \frac{1}{4} (1+ \frac{1}{2}sin t)oz/gal\\\\\\ \frac{1}{2} (1+ \frac{1}{2}sin t)oz/min\\\\\\Rate_{out}=2gal/min \times\frac{Q}{100}oz/gal\\\\\frac{Q}{50}oz/min$

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