Answer:
A. Create radioactive waste i believe
Explanation:
Answer:
51.2 mi/h
Explanation:
Total distance, d = 100 miles
First 60 miles with speed 55 mi/h
Next 40 miles with speed 75 mi/h
Time taken for first 60 miles, t1 = 60 / 55 = 1.09 h
Time taken for 40 miles, t2 = 40 / 75 = 0.533 h
Time spent to get stuck, t3 = 20 min = 0.33 h
Total time, t = t1 + t2 + t3 = 1.09 + 0.533 + 0.33 = 1.953 h
The average speed is defined as the ratio of total distance traveled to the total time taken.
Average speed = 
Thus, the average speed of the journey is 51.2 mi/h.
Answer:
a). va=17.23
or 38.54 mph
b). v=38.54 mph and limit is 35 mph
c). Completely inelastic
d). Eka=192.967 kJ
Ekt=76.071 kJ
Explanation:

The motion is an inelastic collision so

The force of the motion is contrarest by the force of friction so

Now with the acceleration can find the time and the velocity final that make the distance 7.25m being united

So the velocity final can be find using this time

a).
Replacing in the first equation the final velocity can find the initial velocity



b).

Velocity limit in m/s is 15.646 m/s and the initial velocity is 17.23 m/s
so is exceeding the speed limit in about 1.58 m/s
or in miles per hour
3.5 mph
c).
The collision is complete inelastic because any mass can be returned to the original mass, so even they are no the same mass however in the moment they move the distance 7.25m as a same mass the motion is considered completely inelastic
d).

<span>The angular momentum of a particle in orbit is
l = m v r
Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2"
m_1 v_1 r_1 = m_2 v_2 r_2
Assuming that the mass did not change, conservation of angular momentum demands that
v_1 r_1 = v_2 r_2
or
v1 = v_2 (r_2/r_1)
Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have
v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s
Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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