Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
r = 740 m
g = 9.8 m/s²
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
A screwdriver is used to pry the lid off a paint can. The resistance arm is 0.5 cm long and the effort arm is 20 cm long. What i
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Answer:
24.3 degrees
Explanation:
A car traveling in circular motion at linear speed v = 12.8 m/s around a circle of radius r = 37 m is subjected to a centripetal acceleration:
Let α be the banked angle, as α > 0, the outward centripetal acceleration vector is split into 2 components, 1 parallel and the other perpendicular to the road. The one that is parallel has a magnitude of 4.43cosα and is the one that would make the car slip.
Similarly, gravitational acceleration g is split into 2 component, one parallel and the other perpendicular to the road surface. The one that is parallel has a magnitude of gsinα and is the one that keeps the car from slipping outward.
So
Answer:
Explanation:
-The only relevant force is the electrostatic force
-The formula for the electrostatic force is:
E is the electric field and q is the magnitude of the charge.
#Since the electric field is the same in both cases, and the charge of the protons and electrons have the same magnitude, you can state that the magnitude of the electric forces acting in both proton and electron are the same.
-Applying Newton's 2nd Law:
#equate the two forces:
#The equations for velocity in uniform acceleration:
#For the proton:
#For the electron:
The mass values of the proton and electron are:
The speed of the ion is therefore calculated as:
Hence, the ion's speed at the negative plate is