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notsponge [240]
1 year ago
13

A ball on a string travels once around a circle with a circumference of 2.0 m. The tension in the string is 5.0 N. how much work

is done by tension?
Physics
1 answer:
SpyIntel [72]1 year ago
4 0

Answer:0

Explanation:

Given

circumference of circle is 2 m

Tension in the string T=5 N

2\pi r=2

r=\frac{2}{2\pi }=\frac{1}{\pi }=0.318 m

In this case Force applied i.e. Tension is Perpendicular to the Displacement therefore angle between Tension and displacement is 90^{\circ}

W=\int\vec{F}\cdot \vec{r}

W=\int Fdr\cos 90

W=0

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What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade?
kaheart [24]

Incomplete question.The complete question is here

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.

Answer:

F= 0.034 N

Explanation:

Given Data

Outer=2 cm

Edge of blade=21 cm

Mass=7.7 g

Length of blade=21 cm

The last 2cm is treated as if they were at a point 20cm from the center of rotation

To Find

Force=?

Solution

Convert the given frequency to angular frequency

ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)

ω= 3/2*π rad/sec

Now to find centripetal force.

F = m×v²/r

F= m×ω²×r

Put the data

F = 0.0077 kg × (3/2×π rad/sec )²× 0.20 m

F= 0.034 N

3 0
1 year ago
A bullet starting from rest accelerates uniformly at a rate of 1,250 meters per square second. What is the bullet's speed after
Tatiana [17]

Answer:

125,000

Explanation:

8 0
1 year ago
An automobile tire is filled to a pressure of 240.0 kPa early in the morning when the temperature is 15.0C. After the car is dri
yuradex [85]

Answer:

<h2> 242.5kPa</h2>

Explanation:

According to one of the gas laws, \frac{P1}{T1} =\frac{P2}{T2}

Given P1 = 240.0kPa, T1, 15.0°C, T2 = 18.0°C, P2 = ?

Substituting this values into the equation, we have;

\frac{240}{15+273} =\frac{P2}{18+273}\\\frac{240}{288} =\frac{P2}{291}\\

Cross multiplying we have;

288P2 = 240*291

P2 = \frac{240*291}{288} \\P2 = 242.5kPa

The new pressure is 242.5kPa

5 0
1 year ago
The cantilever beam AB has a rectangular cross section of 150 × 200 mm. Knowing that the tension in the cable BD is 10.8 kN and
tatyana61 [14]

Answer:

Explanation:

Find attached the solution

6 0
1 year ago
A 1.47-newton baseball is dropped from a height of 10.0 meters and falls through the air to the ground. The kinetic energy of th
vagabundo [1.1K]

Answer:

The maximum amount of mechanical energy converted to internal energy during the fall is 26.7 joules

Explanation:

Potential Energy (PE) = weight of baseball × height = 1.47N × 10m = 14.7Nm = 14.7 joules

Kinetic Energy (KE) = 12 joules

Maximum amount of mechanical energy converted to internal energy during the fall = PE + KE = 14.7 joules + 12 joules = 26.7 joules

8 0
1 year ago
Read 2 more answers
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