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Allisa [31]
1 year ago
15

A 1.47-newton baseball is dropped from a height of 10.0 meters and falls through the air to the ground. The kinetic energy of th

e ball is 12.0 joules the instant before the ball strikes the ground. The maximum amount of mechanical energy converted to internal energy during the fall is_________.
Physics
2 answers:
vagabundo [1.1K]1 year ago
8 0

Answer:

The maximum amount of mechanical energy converted to internal energy during the fall is 26.7 joules

Explanation:

Potential Energy (PE) = weight of baseball × height = 1.47N × 10m = 14.7Nm = 14.7 joules

Kinetic Energy (KE) = 12 joules

Maximum amount of mechanical energy converted to internal energy during the fall = PE + KE = 14.7 joules + 12 joules = 26.7 joules

Vedmedyk [2.9K]1 year ago
7 0

Answer:

ΔE<em>internal </em>= - 2.7 J

Explanation:

Given

W = m*g = 1.47 N

h<em>initial</em> = 10.0 m

K<em>final</em> = 12.0 J

We can apply

ΔE = ΔE<em>internal</em>

then

ΔE = (K<em>final</em> + U<em>final</em>) - (K<em>initial</em> + U<em>initial</em>)

⇒   ΔE = (K<em>final</em> + 0 J) - (0 J + U<em>initial</em>) = K<em>final </em>- U<em>initial</em>

⇒   ΔE = K<em>final</em> - (W*h<em>final</em>) = 12 J  - (1.47 N*10.0 m)

⇒   ΔE = 12 J - 14.7 J = - 2.7 J

then

ΔE<em>internal </em>= - 2.7 J

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