Answer:
0.0059
Explanation:
According to the question the seismic activity density is given by

Here,
Number of Earthquakes over a given time span = 424
The land area affected = 71300 mi²
So,

The seismic activity density is 0.0059
To be able to identify that the object is in the same motion, we should find the graphs that has an increasing slope of displacement and with the constant velocity with varying time. Graphs on letter D satisfies these requirements.
<em>ANSWER: D</em>
Answer:
r= 2.17 m
Explanation:
Conceptual Analysis:
The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:
E= 2k*(λ/r) Formula (1)
Where:
E: electric field .( N/C)
k: Coulomb electric constant. (N*m²/C²)
λ: linear charge density. (C/m)
r : distance from the charge line to the surface where E calculates (m)
Known data
E= 2.9 N/C
λ = 3.5*10⁻¹⁰ C/m
k= 8.99 *10⁹ N*m²/C²
Problem development
We replace data in the formula (1):
E= 2*k*(λ/r)
2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)
r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)
r= 2.17 m
acceleration of rocket is given here as

now we know that

now integrating both sides



here since its given that rocket will accelerate for t = 10 s
so here we have


so after t = 10 s the speed of rocket will be 130 m/s upwards