Which pair of graphs represent the same motion of an object
2 answers:
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Answer:
26 days
Explanation:
m = 9.4×1021 kg
r= 1.5×108 m
F = 1.1×10^ 19 N
We know Fc =
==> 1.1 × = (9.4 ×
×
) ÷ 1.5 ×
==> 1.1 × =
× 6.26×
==> = 1.1 ×
÷ 6.26×
==> = 0.17571885 ×
==> v= 0.419188323 × m/sec
==> v= 419.188322834 m/s
Putting value of r and v from above in ;
T= 2πr ÷ v
==> T= 2×3.14×1.5× ÷ 0.419188323 ×
==> T = 22.472× 100000 = 2247200 sec
but
86400 sec = 1 day
==> 2247200 sec= 2247200 ÷ 86400 = 26 days
Refer to the diagram shown below.
The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²
After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2
The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁
The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.
Conservation of energy requires that the loss in KE be accounted for as thermal energy.
Answer: 1/2
The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²
After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2
The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁
The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.
Conservation of energy requires that the loss in KE be accounted for as thermal energy.
Answer: 1/2