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Alex
2 years ago
13

Which pair of graphs represent the same motion of an object

Physics
2 answers:
ASHA 777 [7]2 years ago
6 0
To be able to identify that the object is in the same motion, we should find the graphs that has an increasing slope of displacement and with the constant velocity with varying time. Graphs on letter D satisfies these requirements.

<em>ANSWER: D</em>
tresset_1 [31]2 years ago
6 0

Answer:

c

Explanation:

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A ray of yellow light ( f = 5.09 × 1014 hz) travels at a speed of 2.04 × 108 meters per second in
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Velocity = fλ

where f is frequency in Hz, and λ is wavelength in meters.

<span>2.04 * 10⁸ m/s =  5.09 * 10¹⁴  Hz   *  λ </span>

<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴  Hz ) = λ </span>

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2 years ago
1. A 9.4×1021 kg moon orbits a distant planet in a circular orbit of radius 1.5×108 m. It experiences a 1.1×1019 N gravitational
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Answer:

26 days

Explanation:

m = 9.4×1021 kg

r= 1.5×108 m

F = 1.1×10^ 19 N

We know Fc = \frac{m v^{2} }{r}

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==> 1.1 × 10^{19} = v^{2} × 6.26×10^{13}

==> v^{2} =  1.1 × 10^{19} ÷ 6.26×10^{13}

==> v^{2} = 0.17571885 × 10^{6}

==> v= 0.419188323 × 10^{3} m/sec

==> v= 419.188322834 m/s

Putting value of r and v from above in ;

T= 2πr ÷ v

==> T= 2×3.14×1.5×10^{8} ÷ 0.419188323 × 10^{3}

==> T = 22.472× 100000 = 2247200 sec

but

86400 sec = 1 day

==> 2247200 sec= 2247200 ÷ 86400 = 26 days

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2 years ago
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Refer to the diagram shown below.

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After an inelastic collision, the two masses stick together.
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v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
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       = (1/4)mu²
      = (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer:  1/2 

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<span> Rising, warm, moist air masses cool and release precipitation as they rise and then at high altitude, cool
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