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topjm [15]
2 years ago
8

Based on the article “Will the real atomic model please stand up?,” why did J.J. Thomson experiment with cathode ray tubes? to s

pecifically identify the nucleus as a separate part of an atom to determine that electric beams in cathode ray tubes were actually made of particles to prove John Dalton and Democritus wrong to determine the exact energy output of cathode ray tubes
Physics
1 answer:
PIT_PIT [208]2 years ago
3 0

Answer:

B.) to determine that electric beams in cathode ray tubes were actually made of particles

Explanation:

This is the right answer i just took the quiz on edge.

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An alpha particle is identical to a(n) _____.
Alexxx [7]
Helium atom,  in other words, it consistis of a particle having four protons and two neutrons.
3 0
2 years ago
Read 2 more answers
The initial velocity of a 4.0-kg box is 11 m/s, due west. After the box slides 4.0 m horizontally, its speed is 1.5 m/s. Determi
ankoles [38]

Answer:

F = - 59.375 N

Explanation:

GIVEN DATA:

Initial velocity = 11 m/s

final velocity = 1.5 m/s

let force be F

work done =  mass* F = 4*F

we know that

Change in kinetic energy = work done

kinetic energy = = \frac{1}{2}*m*(v_{2}^{2}-v_{1}^{2})

kinetic energy = = \frac{1}{2}*4*(1.5^{2}-11^{2}) = -237.5 kg m/s2

-237.5 = 4*F

F = - 59.375 N

7 0
2 years ago
If a 5.0 kg box is pulled simultaneously by a 10.0 N force and a 5.0 N force, then its acceleration must be?
kicyunya [14]

For this case we have that by definition:

F = ma

Where,

  • <em>m: mass of the object </em>
  • <em>a: acceleration of the object </em>
  • <em>F: summation of forces </em>

We have then:

F = 10 + 5\\F = 15 N

Then, by clearing the acceleration we have:

a = \frac {F} {m}

Substituting values we have:

a = \frac {15} {5}\\a = 3 \frac {m} {s ^ 2}

Answer:

The acceleration of the box is equal to:

a = 3 \frac {m} {s ^ 2}

6 0
1 year ago
The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr
VladimirAG [237]

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

<u>Explanation:</u>

Given data,

E= 3 ×10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E= -ΔV/Δx

ΔV=- E × Δx

ΔV =-3 ×10 ⁶ . 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

6 0
2 years ago
A bicyclist travels the first 800 m of a trip 1.4 minutes, the next 500 m in 1.6 minutes, and finishes up the final 1200 m in 2
soldier1979 [14.2K]

Answer:

 v_average = 500 m / min

Explanation:

Average speed is defined

         v = (x_{f} -x₀) / Δt

let's look in each section

section 1

the variation of the distance is 800 in a time of 1.4 min

         v₁ = 800 / 1.4

         v₁ = 571.4 m / min

section 2

distance interval 500 in a 1.6 min time interval

         v₂ = 500 / 1.6

         v₂ = 312.5 m / min

section 3

distance interval 1200 m in a time 2 min

         v₃ = 1200/2

         v₃ = 600 m / min

taking the speed of each section we can calculate the average speed

         

the distance traveled

        Δx = 800 + 500 + 1200

        Δx = 2500 m

the time spent

        Δt = 1.4 + 1.6+ 2

        Δt = 5 min

         v_average = Δx / Δt

         v_average = 2500/5

         v_average = 500 m / min

7 0
2 years ago
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