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2 years ago

9

A rod 16.0 cm long is uniformly charged and has a total charge of -25.0 µC. Determine the magnitude and direction of the electri

c field along the axis of the rod at a point 42.0 cm from its center.

1 answer:

Vlada [557]2 years ago

8 0

Answer:

-1.4x10^6N/C

Explanation:

Pls see attached file

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The basic function of an automobile carburetor is to atomize the gasoline and mix it with air to promote rapid combustion. Assum

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Answer:

$A = 7.5 \times 10^6 m^2$

Explanation:

Since volume of all the liquid is always conserved

so here we know that

$V_{total} = N V$

$25 cm^3 = N(\frac{4}{3}\pir^3)$

$25 = N (\frac{4}{3} \pi (1.0 \times 10^{-5})^3)$

$N = 5.97 \times 10^{15}$

now we know that total surface area is given as

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A 6.0-Ï‰ and a 12-Ï‰ resistor are connected in parallel across an ideal 36-v battery. What power is dissipated by the 6.0-Ï‰ res

Elena L [17]

Answer:

P = 216 Watts

Explanation:

Given that,

Resistance 1, $R_1=6\ \Omega$

Resistance 2, $R_2=12\ \Omega$

Voltage, V = 36 V

We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.

Firstly, lets find current of the 6 ohms resistor such that,

V = IR

$I=\dfrac{V}{R}\\\\I=\dfrac{36}{6}\\\\I=6\ A$

The power dissipated by 6 ohms resistor is given by :

$P=I^2R$

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So, the power dissipated across 6 ohm resistor is 126 watts.

8 0

1 year ago

Consider two waves defined by the wave functions y1(x,t)=0.50msin(2π3.00mx+2π4.00st) and y2(x,t)=0.50msin(2π6.00mx−2π4.00st). Wh

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Answer:

They two waves has the same amplitude and frequency but different wavelengths.

Explanation: comparing the wave equation above with the general wave equation

y(x,t) = Asin(2Πft + 2Πx/¶)

Let ¶ be the wavelength

A is the amplitude

f is the frequency

t is the time

They two waves has the same amplitude and frequency but different wavelengths.

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An electric heater containing two heating wires X and Y is connected to a power supply of electromotive force(emf) 9.0V and negl

mina [271]

Answer:

0.4 ohms.

Explanation:

From the circuit,

The voltage reading in the voltmeter = voltage drop across each of the parallel resistance.

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R' = (R1×R2)/(R1+R2)

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