I attached the missing picture.
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.

Then, while the car is traveling down the track it loses some of its initial energy due to friction:

So, we know that the car is approaching the point B with the following amount of energy:

The law of conservation of energy tells us that this energy must the same as the energy at point B.
The energy at point B is the sum of car's kinetic and potential energy:

As said before this energy must be the same as the energy of a car approaching the loop:

Now we solve the equation for

:
#1
so mass number = 238
mass number = protons + neutrons
given that
neutrons = 146
238 = protons + 146
protons = 92
#2

so mass number = 241
mass number = protons + neutrons
given that
Protons = 94
241 = 94 + neutrons
neutrons = 147
#3

A = mass number
Protons = 90
Neutrons = 137
A = protons + Neutrons
A = 90 + 137 = 227
Answer:
The answer to your question is Decrease
Answer:
The angular magnification is 
Explanation:
From the question we are told
The focal length is 
The near point is 
The angular magnification is mathematically represented as

Substituting values

Answer:
475
Explanation:
Cori does not exert any more force than 475 J, so 475 is the answer.