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koban [17]
2 years ago
12

In an experiment, one of the forces exerted on a proton is F⃗ =−αx2i^, where α=12N/m2. What is the potential-energy function for

F⃗ ? Let U=0 when x=0.
Physics
1 answer:
Blizzard [7]2 years ago
7 0

Answer:

The potential energy is -4x^3

Explanation:

Given that,

Force F=-\alpha x^2 i

We need to calculate the potential energy

Using formula of work done

\Delta U=F(x) dx

Put the value of F

\Delta U=-\alpha x^2\ dx

On integration

U=-\alpha \dfrac{x^3}{3}+C

U=-\dfrac{\alpha x^3}{3}+C...(I)

U = 0, x = 0 so C = 0

Put the value of c and α in equation (I)

U=-\dfrac{12x^3}{3}+0

U=-4x^3

Hence, The potential energy is -4x^3

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A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
lesya692 [45]

Answer:

H = 109.14 cm

Explanation:

given,                                                            

Assume ,                                                            

Total energy be equal to 1 unit                                

Balance of energy after first collision = 0.78 x 1 unit

                                                             = 0.78 unit

Balance after second collision = 0.78 ^2 unit

                                                   = 0.6084 unit

Balance after third collision = 0.78 ^3 unit

                                              = 0.475 unit

height achieved by the third collision will be equal to energy remained                                        

H be the height achieved after 3 collision

0.475 ( m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

H = 1.0914 m                      

H = 109.14 cm                      

6 0
2 years ago
A solution is oversaturated with solute. Which could be done to decrease the oversaturation?
salantis [7]
Ans: Dilute the solution

Explanation:
To decrease the over-saturation, dilute the solution. Dilution<span> is the process of decreasing the solute's concentration in the </span>solution. It is<span> usually done by mixing with more solvent. In other words, to </span>dilute<span> a </span>solution<span> means to add more solvent without the addition of more solute.</span>
3 0
2 years ago
Read 2 more answers
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0
2 years ago
When you apply the torque equation ∑τ = 0 to an object in equilibrium, the axis about which torques are calculated:
kupik [55]

Answer:

option D.

Explanation:

The correct answer is option D.

When an object is in equilibrium torque calculated at any point will be equal to zero.

An object is said to be in equilibrium net moment acting on the body should be equal to zero.

If the net moment on the object is not equal to zero then the object will rotate it will not be stable.

3 0
2 years ago
What type of system would allow light and air to enter and exit?
BartSMP [9]

Answer:

Closed

Explanation:

8 0
2 years ago
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