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Contact [7]
2 years ago
5

A 1.45 kg falcon catches a 0.515 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is

initially 26.5 m/s and the dove's velocity is 4.95 m/s in the same direction?
Physics
1 answer:
True [87]2 years ago
8 0

Answer:

Their velocity after the impact is 20.85 m/s.                            

Explanation:

Given that,

Mass of falcon, m_1=1.45\ kg

Mass of dove, m_2=0.515\ kg

Initial speed of the falcon, u_1=26.5\ m/s

Initial speed of the dove, u_2=4.95\ m/s

We need to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{1.45\times 26.5+0.515\times 4.95}{(1.45+0.515)}\\\\V=20.85\ m/s

So, their velocity after the impact is 20.85 m/s.                          

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Answer:

5.76 round off to 6

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now 1 roll covers 50 square feet

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2 years ago
A certain alarm clock ticks four times each second, with each tick representing half a period. The balance wheel consists of a t
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Explanation:

The inertia can be find using

a.

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r=0.54 cm * \frac{1m}{100cm} =5.4x10^{-3}m

I = 9.5x10^{-4}kg*(5.4x10^{-3}m)^2

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Solve to K'

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3 0
2 years ago
Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s. I
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Momentum question. This is an inelastic collision, so 

m1v1+m2v2=Vf(m1+m2)
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2 years ago
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The question above can be answered through using the concept of Conservation of Momentum which may be expressed as,
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mr Goodwill [35]
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3 0
2 years ago
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