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Contact [7]
2 years ago
5

A 1.45 kg falcon catches a 0.515 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is

initially 26.5 m/s and the dove's velocity is 4.95 m/s in the same direction?
Physics
1 answer:
True [87]2 years ago
8 0

Answer:

Their velocity after the impact is 20.85 m/s.                            

Explanation:

Given that,

Mass of falcon, m_1=1.45\ kg

Mass of dove, m_2=0.515\ kg

Initial speed of the falcon, u_1=26.5\ m/s

Initial speed of the dove, u_2=4.95\ m/s

We need to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{1.45\times 26.5+0.515\times 4.95}{(1.45+0.515)}\\\\V=20.85\ m/s

So, their velocity after the impact is 20.85 m/s.                          

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