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Ksivusya [100]
2 years ago
9

A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier

. Determine the equivalent resistance of the three speakers, assuming that they all behave as resistors.
Physics
1 answer:
kolbaska11 [484]2 years ago
6 0

Answer:

2.286 ohm

Explanation:

R1 = 16 ohm

R2 = 8 ohm

R3 = 4 ohm

They all are connected in parallel combination

Let the equivalent resistance is R.

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/16 + 1/8 + 1/4

1/R = (1 + 2 + 4) / 16

1/R = 7 / 16

R = 16/7 = 2.286 ohm

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A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the neg
WINSTONCH [101]

Answer:

=2,012,319.36 \ m/s

Explanation:

-The only relevant force is the electrostatic force

-The formula for the electrostatic force is:

F = Eq

E is the electric field and q is the magnitude of the charge.

#Since the electric field is the same in both cases, and the charge of the protons and electrons have the same magnitude, you can state that the magnitude of the electric forces acting in both proton and electron are the same.

F_e = F_p\\\\F_e= Force \ on \ electron\\F_p = Force \ on \ proton

-Applying Newton's 2nd Law:

F=ma

F_e=M_ea_e

F_p=M_pa_p

#equate the two forces:

F_e = F_p\\\\M_ea_e=M_pa_p\\\\a_e=\frac{M_pa_p}{M_e}

#The equations for velocity in uniform acceleration:

V_f^2=V_o^2+2ad\\\\V_o^2=0\\\\\therefore V_f^2=2ad

#For the proton:

V_f^2=2a_pd\\\\a_p=\frac{V_f^2}{2d}\\\\a_p=\frac{47000m/s)^2}{2d}

#For the electron:

V_f^2=2{a_e}^2\times 2d\\\\A_e=M_p\times A_p/M_e\\\\V_f^2=M_p\times (47000m/s)^2/2d\times2d/M_e\\\\V_f^2=M_p\times (47000m/s)^2/M_e\\\\V_f=47000m/s\times\sqrt{\frac{M_p}{M_e}}

The mass values of the proton and electron are:

M_p=1.67\times 10^{-27} kg\\\\M_e=9.11\times10^{-31}kg

The speed of the ion is therefore calculated as:

V_f=47000m/s\times\sqrt{\frac{M_p}{M_e}}\\\\=47000m/s\times\sqrt{\frac{1.67\times10^{-27}}{9.11\times10^{-31}}\\\\=2,012,319.36 \ m/s

Hence, the ion's speed at the negative plate is =2,012,319.36 \ m/s

7 0
2 years ago
_____ has a longer wavelength than _____. _____ has a longer wavelength than _____. Blue ... green Green ... yellow Red ... gree
nadya68 [22]

Answer:

red has a longer wavelength than yellow. Yellow has a longer wavelength than green.

Explanation

in the visible spectrum a color with high frequency  contains shorter wavelength.In this case red color has high wavelength followed by yellow followed by green,blue and violet.

3 0
2 years ago
Read 2 more answers
Imagine that a small boy and his much larger father are enjoying a winter morning, sliding along the ice on a nearby playground.
kramer
You can write an hypothesis such as this:
The weight of an object has effects on the operating frictional force, the greater the weight, the higher the operating frictional force.
The father is the one with the higher weight while the son has the lower weight. The operating frictional force is the friction that their weights exert.
8 0
2 years ago
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A uniform cube with mass 0.700 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.400 m and mass 0.
Sav [38]

Answer:

  44 1/3 cm

Explanation:

The cube has an edge length of ∛0.027 m = 0.3 m, so a center of mass (CoM) 15 cm above the floor.

The sphere's center of mass is 40 cm above the top of the cube, so is 70 cm above the floor. The weighted average of the CoM locations is ...

  ((15 cm)(0.700 kg) +(70 cm)(0.800 kg))/(0.700 kg +0.800 kg)

  = (10.5 kg·cm +56 kg·cm)/(1.500 kg) = 44.333... cm

The center of mass of the two-object system is 44 1/3 cm above the floor.

_____

<em>Comment on the units</em>

We're not familiar with "hcm" as a unit. We presume that you can convert the given answer to the units you desire.

6 0
2 years ago
A nonlinear spring is used to launch a toy car. The car is pushed against the spring, compressing the spring 2.5 cm. The force t
dybincka [34]

Answer:

1.56 J

Explanation:

given,

Spring compression, x = 2.5 cm

Force exerts by the spring,

F = - k x

k = 5000 N/m

Potential energy stored = ?

energy stored in the spring

PE = \dfrac{1}{2}kx^2

PE = \dfrac{1}{2}\times 5000\times 0.025^2

PE = 1.56 J

Hence, the potential energy stored in the car is equal to 1.56 J.

5 0
2 years ago
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