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Kryger [21]
2 years ago
11

Two objects of the same mass travel in opposite directions along a horizontal surface. Object X has a speed of 5ms and object Y

has a speed of 5ms, as shown in the figure. After a period of time, object X collides with object Y. In scenario 1, the objects stick together after the collision. In scenario 2, the objects do not stick together after the collision.
Which of the following claims is true regarding how the outcome of scenario 1 is different from the outcome of scenario 2?
Physics
2 answers:
Papessa [141]2 years ago
8 0

Answer:

1

Explanation:

Because theyre heading opposite directions

alexdok [17]2 years ago
8 0
Since both objects are travelling in opposite directions at the same speed but eventually colliding with each other hence it is obvious that they are travelling in a circle.

Now, this question is regarding the conversation of momentum - elastic / in elastic collision.

Assuming the balls are in a closed system(an assumption that is consistent in your syllabus,unless stated otherwise)as the ball collides, momentum is conserved but some of the energy might be lost due to the collision either through heat / sound.

Summary:

3 types of collision.

1st type: Elastic collision
- No loss in Kinetic Energy
- No loss in momentum
- Balls do not stick together
Example: Bouncing Basketball, the ball comes back to your hand at the same height.

2nd type: Inelastic collision
- Loss in kinetic energy, (heat energy when in contact)
- No loss in momentum
- Balls do not stick together
Example: Bomb explosion.

3rd type: Perfectly Inelastic collision
- Maximum amount of KE is loss
- No loss in momentum
- Balls stick together
Example: Ballistic Pendulum
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A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic
Sunny_sXe [5.5K]

Answer:

Magnetic field will be ZERO at the given position

Explanation:

As we know that the magnetic field due to moving charge is given as

B = \frac{\mu_0 qv sin\theta}{4\pi r^2}

so here we know that for the direction of magnetic field we will use

\hat B = \hat v \times \hat r

so we have

\hat B = \hat i \times (\hat i + 0\hat j + 0\hat k)

so magnetic field must be ZERO

So whenever charge is moving along the same direction where the position vector is given then magnetic field will be zero

3 0
2 years ago
Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl
kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

7 0
2 years ago
A policeman kicks in a door with a force of 4500 N. What force does the door apply to the policeman’s leg?
Soloha48 [4]

Answer:

-4500 N

Source: Brainly

The police officer must be angry 0_0

4 0
2 years ago
The Bernoulli equation is valid for steady, inviscid, incompressible flows with a constant acceleration of gravity. Consider flo
irina1246 [14]

Answer:

p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

Explanation:

first write the newtons second law:

F_{s}=δma_{s}

Applying bernoulli,s equation as follows:

∑δp+\frac{1}{2} ρδV^{2} +δγz=0\\

Where, δp is the pressure change across the streamline and V is the fluid particle velocity

substitute ρg for {tex]γ[/tex] and g_{0}-cz for g

dp+d(\frac{1}{2}V^{2}+ρ(g_{0}-cz)dz=0

integrating the above equation using limits 1 and 2.

\int\limits^2_1  \, dp +\int\limits^2_1 {(\frac{1}{2}ρV^{2} )} \, +ρ \int\limits^2_1 {(g_{0}-cz )} \,dz=0\\p_{1}^{2}+\frac{1}{2}ρ(V^{2})_{1}^{2}+ρg_{0}z_{1}^{2}-ρc(\frac{z^{2}}{2})_{1}^{2}=0\\p_{2}-p_{1}+\frac{1}{2}ρ(V^{2}_{2}-V^{2}_{1})+ρg_{0}(z_{2}-z_{1})-\frac{1}{2}ρc(z^{2}_{2}-z^{2}_{1})=0\\p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

there the bernoulli equation for this flow is p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

note: ρ=density(ρ) in some parts and change(δ) in other parts of this equation. it just doesn't show up as that in formular

4 0
2 years ago
Which of the following selections completes the following nuclear reaction?
Monica [59]

Answer:

n (a neutron)

Explanation:

For a chemical element:

- The lower subscript indicates the atomic number (the number of protons)

- The upper subscript indicates the mass number (the sum of protons and neutrons in the nucleus)

In the reaction described in the problem, we see that a gamma photon hits a nucleus of Calcium-40, which has

Z = 20 (20 protons)

A = 40 (40 protons+neutrons)

Which means that the number of neutrons is n =  A - Z = 40 - 20 = 20

After the reaction, we have a nucleus of Calcium-39, which has

Z = 20 (20 protons)

A = 39 (39 protons+neutrons)

Which means that the number of neutrons is n =  A - Z = 40 - 39 = 19

So, the nucleus has lost 1 neutron, which is the particle missing in the reaction.

3 0
2 years ago
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