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Kryger [21]
2 years ago
11

Two objects of the same mass travel in opposite directions along a horizontal surface. Object X has a speed of 5ms and object Y

has a speed of 5ms, as shown in the figure. After a period of time, object X collides with object Y. In scenario 1, the objects stick together after the collision. In scenario 2, the objects do not stick together after the collision.
Which of the following claims is true regarding how the outcome of scenario 1 is different from the outcome of scenario 2?
Physics
2 answers:
Papessa [141]2 years ago
8 0

Answer:

1

Explanation:

Because theyre heading opposite directions

alexdok [17]2 years ago
8 0
Since both objects are travelling in opposite directions at the same speed but eventually colliding with each other hence it is obvious that they are travelling in a circle.

Now, this question is regarding the conversation of momentum - elastic / in elastic collision.

Assuming the balls are in a closed system(an assumption that is consistent in your syllabus,unless stated otherwise)as the ball collides, momentum is conserved but some of the energy might be lost due to the collision either through heat / sound.

Summary:

3 types of collision.

1st type: Elastic collision
- No loss in Kinetic Energy
- No loss in momentum
- Balls do not stick together
Example: Bouncing Basketball, the ball comes back to your hand at the same height.

2nd type: Inelastic collision
- Loss in kinetic energy, (heat energy when in contact)
- No loss in momentum
- Balls do not stick together
Example: Bomb explosion.

3rd type: Perfectly Inelastic collision
- Maximum amount of KE is loss
- No loss in momentum
- Balls stick together
Example: Ballistic Pendulum
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acceleration of rocket is given here as

a_y = 2.60* t

now we know that

\frac{dv}{dt} = 2.60t

now integrating both sides

\int dv = \int 2.60t dt

v = 2.60\frac{t^2}{2}

v = 1.30 t^2

here since its given that rocket will accelerate for t = 10 s

so here we have

v = 1.30 * 10^2

v = 130 m/s

so after t = 10 s the speed of rocket will be 130 m/s upwards

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You are on vacation in San Francisco and decide to take a cable car to see the city. A 5800-kgkg cable car goes 260 mm up a hill
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4.325\times10^6J

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Hence, total change in energy = mgh = 5800\times9.81\times76.0166J=4.325\times10^6J

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2 years ago
What does the term equilibrium refer to?
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A) the resting position of the wave

<h3><u>Explanation</u>;</h3>
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2 years ago
Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is  Av with A the cross section area and v the velocity,

so,

A_1V_1=A_2V_2

A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}

the diameter decreases 86% so

d_2 = 0.86d_1

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}

Thus, speed in smaller section is 48.6 m/s

3 0
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