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2 years ago

12

A car drives toward the right over the top of a hill, as shown below. An illustration of car at the top of a hill pointing right

and looking at the side of the car. The is a vector up labeled Z, a vector down labeled X, a vector left labeled Y and a vector right labeled W. Which arrow represents the centripetal acceleration? W X Y Z

2 answers:

Sav [38]2 years ago

6 0

Answer: X

Explanation:

This situation can be illustrated as a car in circular motion (image attached).

In circular motion the acceleration vector $\vec{a}$ is always directed toward the center of the circumference (that's why it's called centripetal acceleration).

So, in this case the arrow labeled X is the only that points toward the center, hence it represents the car's centripetal acceleration

kherson [118]2 years ago

3 0

Answer:

X

Explanation:

Because Centripetal Force pulls it towards the circle's center

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A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106

defon

Answer:

$4.7\cdot 10^{-14}N$

Explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

$F=qvB$

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

$q=1.6\cdot 10^{-19} C$

$v=6.5\cdot 10^6 m/s$

$B=4.5\cdot 10^{-2} T$

So the force experienced by the electrons is

$F=(1.6\cdot 10^{-19}C)(6.5\cdot 10^6 m/s)(4.5\cdot 10^{-2} T)=4.7\cdot 10^{-14}N$

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2 years ago

What is the net force acting on the buggy?<br> N<br> The net force is pointing to the...

blagie [28]

Answer:

390, right

Explanation:

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2 years ago

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Pions have a half-life of 1.8 x 10^-8 s. A pion beam leaves an accelerator at a speed of 0.8c. What is the expected distance ove

Nuetrik [128]

Answer:

the expected distance is 4.32 m

Explanation:

given data

half life time = 1.8 × $10^{-8}$ s

speed = 0.8 c = 0.8 × 3 × $10^{8}$

to find out

expected distance over

solution

we know c is speed of light in air is 3 × $10^{8}$ m/s

we calculate expected distance by given formula that is

expected distance = half life time × speed .........1

put here all these value

expected distance = half life time × speed

expected distance = 1.8 × $10^{-8}$ × 0.8 × 3 × $10^{8}$

expected distance = 4.32

so the expected distance is 4.32 m

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2 years ago

Ariel dropped a golf ball from her second story window. The ball starts from rest and hits the sidewalk 3.5 s later with a veloc

Aleks [24]

Answer:

By using the acceleration formula,

$a = \frac{v - u}{t}$

$a = \frac{14.7 - 0}{3.5}$

$a = 4.2m \: s ^{ - 2}$

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2 years ago

A measuring cylinder contains 60cm3 of oil at 0 celcius. When a piece of ice was roped into the cylinder it sank completely in o

mariarad [96]

Answer:

$S_i=\frac{9}{10} =0.9$

Explanation:

Given:

volume of oil in the cylinder, $V_o=60\ cm^2$

volume of the oil level when the ice is immersed, $V=90\ cm^3$

the volume level of oil when the ice melted, $V'=87\ cm^3$

<u>Now, therefore the volume of ice:</u>

$V_i=V-V_o$

$V_i=90-60$

$V_i=30\ cm^3$

<u>Now the volume of water:</u>

$V_w=V'-V_o$

$V_w=87-60$

$V_w=27\ cm^3$

As we know that the relative density is the ratio of density of the substance to the density of water.

<u>So, the relative density of ice:</u>

$S_i=\frac{\rho_i}{\rho_w}$ .....................(1)

as we know that density is given as:

$\rm \rho=\frac{mass}{volume}$

now eq. (1)

$S_i=\frac{m}{V_{i}}\div \frac{m}{V_w}$

where, m = mass of the water or the ice which remains constant in any phase

$S_i=\frac{V_w}{V_i}$

$S_i=\frac{27}{30}$

$S_i=\frac{9}{10} =0.9$

7 0

2 years ago