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juin [17]
2 years ago
14

Can a force directed north balance a force directed east

Physics
1 answer:
aksik [14]2 years ago
6 0
No. 
East-force can only be balanced by west-force.
North-force has no west-force in it, no matter how strong it is.
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a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe
e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by 0.5I\omega^{2} where I is moment of inertia which is given by mr^{2} and here m is mass, r is radius. Also, v=\omega r hence making \omega the subject then \omega=\frac {v}{r} where v is the velocity.

Rotational kinetic energy=0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}

This is same as the formula for translational kinetic energy which is given by 0.5mv^{2}

Therefore, total kinetic energy= 0.5mv^{2}+0.5mv^{2}=mv^{2}

Substituting m with 2 kg and v with 6 m/s then total energy will be 2\times 6^{2}=72 J

7 0
2 years ago
What is a manifest function of a married father joining the military
katovenus [111]

Answer:

Explanation:

Manifest- he supports his family, fights for a living. He will support his family while he fights for a living it is basically his job. By fighting in war that is what income his family will get

6 0
2 years ago
Read 2 more answers
What would the speed of each particle be if it had the same wavelength as a photon of yellow light (????=575.0 nm)? Proton (mass
PilotLPTM [1.2K]

Answer:

Proton: v=0.689 m/s

Neutron: v=0.688 m/s

Electron: v=1265.078 m/s

Alpha particle: v=0.173 m/s

Explanation:

De Broglie equation allows you to calculate the “wavelength” of an electron or any other particle or object of mass m that moves with velocity v:

λ=\frac{h}{mv}

h is the Planck constant: 6.626×10⁻³⁴\frac{kg.m^2}{s}

We know that the wavelength of the particle is 575 nm (575×10⁻⁹m), so we find the velocity v for each particle:

λ=\frac{h}{mv}

v=h÷(mλ)

<u>Proton:</u>

m=1.673×10⁻²⁴ g · \frac{1kg}{1000g}=1.673×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(1.673×10⁻²⁷ kg×575×10⁻⁹m)

v=0.689 m/s

<u>Neutron:</u>

m=1.675×10⁻²⁴ g · \frac{1kg}{1000g}=1.675×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(1.675×10⁻²⁷ kg×575×10⁻⁹m)

v=0.688 m/s

<u>Electron:</u>

m= 9.109×10⁻²⁸ g · \frac{1kg}{1000g}=9.109×10⁻³¹ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(9.109×10⁻³¹ kg×575×10⁻⁹m)

v=1265.078 m/s

<u>Alpha particle:</u>

m=6.645×10⁻²⁴ g · \frac{1kg}{1000g}=6.645×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴\frac{kg.m^2}{s}÷(6.645×10⁻²⁷ kg×575×10⁻⁹m)

v=0.173 m/s

3 0
2 years ago
Read 2 more answers
A 125g steel ball with a kinetic energy of .25j rolls along a horizontal track how high up an inclined track will the ball roll
Sauron [17]
E = 0.25 = m*g*h 
<span>h = 0.25/(m*g) = 0.25/(0.125*10) = 0.25/1.25 = 1/5 = 0.20 m
I hope this helps you have a great day and im sorry it took so long to get an answer</span>
6 0
2 years ago
Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
AnnyKZ [126]
The statement that can be used to answer this  question is:

"If the cylinder is brought higher then, its temperature when brought down becomes higher because a greater amount of potential energy is converted to thermal energy."

The potential energy is converted to thermal energy when the object is released the velocity becomes higher because of the acceleration due to gravity.
8 0
2 years ago
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