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juin [17]
2 years ago
14

Can a force directed north balance a force directed east

Physics
1 answer:
aksik [14]2 years ago
6 0
No. 
East-force can only be balanced by west-force.
North-force has no west-force in it, no matter how strong it is.
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Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
AnnyKZ [126]
The statement that can be used to answer this  question is:

"If the cylinder is brought higher then, its temperature when brought down becomes higher because a greater amount of potential energy is converted to thermal energy."

The potential energy is converted to thermal energy when the object is released the velocity becomes higher because of the acceleration due to gravity.
8 0
2 years ago
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Calculate the force of Earth’s gravity on a spacecraft 2.00 Earth radii above the Earth’s surface (That would be 3.00 Earth radi
igomit [66]

Answer:

2014.44 N

Explanation:

mass of spacecraft, m = 1850 kg

distance r = 3 x R

where r be the radius of earth.

g be the acceleration due to gravity on the surface of earth and g' be the acceleration due to gravity at height

\frac{g'}{g}=\left (\frac{R}{r}  \right )^{2}

\frac{g'}{g}=\left (\frac{R}{3R}  \right )^{2}

g' = g / 9

g' = 9.8 / 9 = 1.089 m/s²

Force of gravity on the space craft

F = m g' = 1850 x 1.089

F = 2014.44 N

Thus, the force of gravity on the space craft at height is 2014.44 N.

3 0
2 years ago
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied​
never [62]

Answer:

6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = \frac{force}{area}

         Force  = Pressure x area

        Force  = 300 x 0.02  = 6N

8 0
2 years ago
A roller coaster, traveling with an initial speed of 15 meters per second, decelerates uniformly at â7.0 meters per second2 to a
Harrizon [31]
<span>By algebra, d = [(v_f^2) - (v_i^2)]/2a. Thus, d = [(0^2)-(15^2)]/(2*-7) d = [0-(225)]/(-14) d = 225/14 d = 16.0714 m With 2 significant figures in the problem, the car travels 16 meters during deceleration.</span>
8 0
2 years ago
A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force resisting the carts moti
-BARSIC- [3]

The force applied by the man is 60 N

Explanation:

We can solve this problem by applying Newton's second law, which states that:

\sum F = ma (1)

where

\sum F is the net force acting on the child+cart

m is the mass of the child+cart system

a is their acceleration

In this problem, we have:

m = 30.0 kg is the mass

a=1.50 m/s^2

And there are two forces acting on the child+cart system:

  • The forward force of pushing, F
  • The force resisting the cart motion, R = 15.0 N

Therefore we can write the net force as

\sum F = F -R

where R is negative since its direction is opposite to the motion

So eq.(1) can be rewritten as

F-R=ma

And solving for F,

F=ma+R=(30.0)(1.50)+15.0=60 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

4 0
2 years ago
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