Answer:
Explanation:
Note : the questions do not come in the right order.
Data:
Mass = 0.0518kg
Velocity = 45 m / s
Distance (s) = 0.44m
C) what's the acceleration on the ball?
Using equation of motion,
V² = u² + 2as
V² - u² = 2as
a = (v² - u²) / 2s
a = (45² - 0) / 2 * 0.44 [the ball was at rest]
a = 2025 / 0.88
a = 2301.136m/s²
D) The net force on the ball?
Force = mass * acceleration
F = m*a
F = 0.0518 * 2301.136
F = 119.199N
The force acting on the ball was 133.465N
F = 133.47N
b) time period the ball was struck.
From the relationship between impulse and momentum,
Ft = m * v
133.47 * t = 0.058 * 45
t = 2.61 / 133.47
t = 0.01955s
a) average velocity (V) = total distance covered / total time taken
V = s / t
V = 0.44 / 0.01955
V = 22.50m/s.
e) if the ball was heavier and still experienced the same velocity, the applied would've been lesser than before.
