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2 years ago

A brick is resting on a rough incline as shown in the figure. The friction force acting on the brick, along the incline, is

Physics

2 answers:

Tasya [4]2 years ago

6 0

B) equal to the gravitational force of the brick

lakkis [162]2 years ago

4 0

Answer:

D) less than the gravitational force of the brick.

Explanation:

When a brick is at rest on the inclined plane

then we will have all forces balanced on the brick

so we will have force balance along the inclined plane given as

$F_g sin\theta = F_f$

$mg sin\theta = F_f$

on the other side we can find force balance perpendicular to the inclined plane

$mg cos\theta = F_n$

so from above equation we can say that friction force is the component of the weight of the object along the inclined plane

so correct answer is

D) less than the gravitational force of the brick.

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The structural diversity of carbon-based molecules is determined by which properties?

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3.the orientation of those bonds in the form of a tetrahedron.

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2 years ago

Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different direc

Advocard [28]

Answer:

the direction that should be walked by Ricardo to go directly to Jane is 23.52 m, 24° east of south

Explanation:

given information:

Ricardo walks 27.0 m in a direction 60.0 ∘ west of north, thus

A= 27

Ax = 27 sin 60 = - 23.4

Ay = 27 cos 60 = 13.5

Jane walks 16.0 m in a direction 30.0 ∘ south of west, so

B = 16

Bx = 16 cos 30 = -13.9

By = 16 sin 30 = -8

the direction that should be walked by Ricardo to go directly to Jane

R = √A²+B² - (2ABcos60)

= √27²+16² - (2(27)(16)(cos 60))

= 23.52 m

now we can use the sines law to find the angle

tan θ = $\frac{R_{y} }{R_{x} }$

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2 years ago

A 40-mH ideal inductor is connected in series with a 50 Ω resistor through an ideal 15-V DC power supply and an open switch. If

sergey [27]

Answer:i=300 mA

Explanation:

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Resistor(R)= $50 \Omega$

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$\tau =\frac{40\times 10^{-3}}{50}=8\times 10^{-4}$

current $i_0=\frac{V}{R}$

$i_0=\frac{15}{50}=0.3 A$

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