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Alina [70]
2 years ago
10

You're driving your pickup truck around a curve that has a radius of 22 m.How fast can you drive around this curve before a stee

l toolbox slides on the steel bed of the truck?
Physics
1 answer:
creativ13 [48]2 years ago
7 0

The maximal speed around this curve before a steel toolbox slides on the steel bed of the truck : <u>14.832 m/s</u>

<h3>Further explanation </h3>

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N

m = mass, Kg

v = linear velocity, m / s

r = radius, m

The speed that is in the direction of the circle is called linear velocity

Can be formulated:

\displaysyle v = 2 \pi.r.f

r = circle radius

f = rotation per second (RPS)

Pickup trucks that move around a curve will experience centripetal forces. So that the steel toolbox does not experience slides on the steel bed of the truck, the centripetal force experienced by the steel toolbox must be the same as its weight. If the centripetal force exceeds the weight of the steel toolbox, the steel toolbox will fall

centripetal force = weight

\rm \dfrac{mv^2}{r}=mg

then the maximal speed so that the steel toolbox doesn't fall :

\rm v^2=r\times g\\\\v=\sqrt{r\times g}

a curve has a radius of 22 m , then

\rm v=\sqrt{22\times 10}\\\\v=\sqrt{220}\\\\v=\boxed{\bold{14.832\:m/s}}}

<h3>Learn more </h3>

the average velocity

brainly.com/question/5248528

resultant velocity

brainly.com/question/4945130

velocity position

brainly.com/question/2005478

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Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart.
m_a_m_a [10]

Answer:

F = 10.788 N

Explanation:

Given that,

Charge 1, q_1=6\ \mu C=6\times 10^{-6}\ C

Charge 2, q_2=2\ \mu C=2\times 10^{-6}\ C

Distance between charges, d = 0.1 m

We know that there is a force between charges. It is called electrostatic force. It is given by :

F=\dfrac{kq_1q_2}{d^2 }\\\\F=\dfrac{8.99\times 10^9\times 6\times 10^{-6}\times 2\times 10^{-6}}{(0.1)^2 }\\\\F=10.788\ N

So, the force applied between charges is 10.788 N.

3 0
2 years ago
Read 2 more answers
The position of an object is given by x = at3 - bt2 + ct,where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI un
Elza [17]

Answer:

The answer to your question is: 15 m/s2

Explanation:

Equation    x = at3 - bt2 + ct

a = 4.1 m/s3

b = 2.2 m/s2

c = 1.7 m/s

First we find  x at t = 4.1 s

x = 4.1(4.1)3 - 2.2(4.1)2 + 1.7(4.1)

x = 4.1(68.921) - 2.2(16.81) + 6.97

x = 282.58 - 36.98 + 6.98

x = 252.58 m

Now we find speed

v = x/t = 252.58/ 4.1 = 61.6 m/s

Finally

acceleration = v/t = 61.6/4.1 = 15 m/s2

6 0
2 years ago
16. A 7500 kg 18-wheeler traveling at 20 m/s exits onto the runaway truck ramp on the freeway.
miskamm [114]

Answer:

<em>765,000 Joule</em>

Explanation:

<u>Principle of Conservation of Energy </u>

The total energy in an isolated system cannot be created or destroyed, but transformed. Moving objects have kinetic energy, objects placed in some height above a reference level have gravitational potential energy. When they change their motion variables, one energy converts into the other, but if the numbers don't fit, we know there was some other type of energy acting into the system. The most common reason for energy 'losses' is the thermal energy, produced when objects move in rough surfaces or take friction from the air.

The 7,500 kg truck is originally traveling at 20 m/s to a certain height we'll set to 0. Thus, its total energy is  

\displaystyle E_1=\frac{mv^2}{2}

\displaystyle E_1=\frac{7,500\ 20^2}{2}

E_1=1,500,000\ Joule

When it comes to a stop, its speed is 0 and its height is 10 m higher than before. It means all the kinetic energy was transformed into other types of energy. The gravitational potential energy is

U=mgh=(7,500)(9.8)(10)=735,000\ Joule

Since this number is not equal to the previous value of the energy, the difference is due to thermal energy dissipated by friction

E_t=1,500,000\ Joule-735,000\ Joule=765,000\ Joule

7 0
2 years ago
A charming friend of yours who has been reading a little bit about astronomy accompanies you to the campus observatory and asks
lidiya [134]

Answer:

b

Explanation:

3 0
2 years ago
A lever has a 36cm input arm and a 6cm output arm. find MA.
Nady [450]

6

Explanation:

The mechanical advantage is a factor that measures how input force increases using a machine.

A lever is a simple machine with the fulcrum at the center.

To calculate the mechanical advantage M.A of levers we use the expression below;

M. A = \frac{F_{b} }{F_{a} } = \frac{a}{b}

F_{a} = input force

F_{b} = output force

a is the distance of the input force from the fulcrum

b is the distance of the output force from the fulcrum

Given

a = 36cm

b = 6cm

M.A = \frac{36cm}{6cm} = 6

learn more:

Torque brainly.com/question/5352966

#learnwithBrainly

6 0
2 years ago
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