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Nutka1998 [239]

1 year ago

6

A ping-pong ball weighs 0.025 N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compres

sed 0.055 m and released, the maximum height above the compressed position that the ball reaches is 2.84 m. Neglect air resistance and determine the spring constant.

1 answer:

kondor19780726 [428]1 year ago

4 0

Answer:

Explanation:

The energy stored in the spring is used to throw the ball upwards . Let the height reached be h

stored energy of spring = 1/2 k y² , k is spring constant and y is compression created in the spring

stored energy of spring = potential energy of the ball

1/2 k y² = mgh , m is mass of the ball , h is height attained by ball

.5 k x .055² = .025 x 2.84

.0015125 k = .071

k = .071 / .0015125

= 46.9 N / m .

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Answer:b

Explanation:

Given

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Answer:

$5.219\,\frac{m}{s}$

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Las condiciones del problema requieren el cálculo de la rapidez inicial de los guijarros. Se sabe que el componente vertical de la rapidez final es cero. Por tanto, el tiempo se determina a continuación: (The conditions of this problems require the calculation of the initial speed of the peebles. It is known that vertical component of the final speed is zero. Therefore, the time is determined herein:).

$(0\,\frac{m}{s})^{2} = v_{o,y}^{2} - 2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.5\,m)$

$v_{o,y} = 9.395\,\frac{m}{s}$

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$v_{o,x} = 5.219\,\frac{m}{s}$

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2 years ago

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Answer:

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Explanation:

It is given that,

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Initial velocity of the puck, $u=(1i+0j)\ m/s$

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